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3 years ago

If f(x) = 27+1, what is f\x) when x = 3? 1

Physics

1 answer:

emmasim [6.3K]3 years ago

5 0

Answer:

f(3) = 28

Explanation:

It is required to find the value of f(x) when x = 3 and the function is given by :

f(x) = 27+1

As the given function is independent of x. So, its value at any value is given by :

f(3) = 28

So, the value of f(3) is equal to 28.

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A 15 kg block is on a ramp which is inclined at 20o above the horizontal. It is connected by a string to a 19 kg mass which hang

12345 [234]

Answer:

The magnitude of the acceleration of the 19 kg block is 1.414 m/s²

Explanation:

From Newton's second law of motion;

$F_{Net} = ma$

where;

m is the mass of the objects involved, kg

a is the acceleration of the object, m/s²

different forces on the block and string

⇒force due to 15 kg block

=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396

= 138.12 N

⇒Tensional Force on 19 kg mass:

T = mg = 19×9.8 = 186.2 N

$F_{Net} = T-mg = a(m_1+m_2)$

186.2 - 138.12 = a(15+19)

48.08 = a(34)

a = 48.08/34

a = 1.414 m/s²

Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²

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4 years ago

What is a tornado? Details

ohaa [14]

A tornado is a natural force It is a very strong wind that causes thing to damage

6 0

4 years ago

Read 2 more answers

momentum A proton interacts electrically with a neutral HCl molecule located at the origin. At a certain time t, the proton’s po

arlik [135]

Answer:

$\ m/s$

Explanation:

F = Force =

m = Mass of proton = $1.7\times 10^{-27\ kg$

t = Time taken = $2\times 10^{-14}\ s$

Acceleration is given by

$a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{}{1.7\times 10^{-27}}\\\Rightarrow a=\ m/s^2$

$v=u+at\\\Rightarrow v=+\times 2\times 10^{-14}\\\Rightarrow v=+\times 2\times 10^{-14}\\\Rightarrow v=+\\\Rightarrow v=\ m/s$

The velocity of the proton is $\ m/s$

6 0

4 years ago

A car is towing a boat on a trailer. The driver starts from rest and accelerates to a velocity of +16.7 m/s in a time of 20.7 s.

frutty [35]

Answer:

F = 479.21 N

Explanation:

given,

initial velocity = 0 m/s

final velocity = 16.7 m/s

time taken = 20.7 s

combined mass of the boat and trailer = 594 kg

tension in the hitch = ?

using equation of motion

v = u + a t

16.7 = 0 + a × 20.7

a = 0.807 m/s²

Force = mass × acceleration

F = 594 × 0.807

F = 479.21 N

Hence, the tension in the hitch that connects the trailer to the car is F = 479.21 N

7 0

3 years ago

A 1000-kg car traveling at 70 m/s takes 3 m to stop under full braking. the same car under similar road conditions, traveling at

azamat

We assume $a=const$ (acceleration is constant. We apply the equation
$v^2=v0^2+2as$ where s is the distance to stop $v=0(m/s)$ . We find the acceleration from this equation
$a=-v0^2/(2s)=-70^2/(2*3) =-816.7 (m/s^2)
$
We know the acceleration, thus we find the distance necesssary to stop when initial speed is $v=140 (m/s)$
$s=-v0^2/(2a) =140^2/(2*816.7)=12 (m)$

5 0

4 years ago