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IgorLugansk [536]
3 years ago
7

A baseball is released at rest from the top of the Washington Monument. It hits the ground after falling for 6 s. What was the h

eight from which the ball was dropped
Physics
1 answer:
alukav5142 [94]3 years ago
6 0

Answer:

Total height (s) = 176.4 m

Explanation:

Given:

Initial velocity (u) = 0 m/s

Time taken (t) = 6 sec

Acceleration due to gravity = 9.8 m/s²

Find:

Total height (s)

Computation:

s = ut + [1/2]gt²

s = (0)(6) + [1/2][9.8][6²]

s = 176.4 m

Total height (s) = 176.4 m

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Answer:

.....,.,.,.,.,.,.,.,.,.,.,.,..,.,.,.,.,.,.,,.,.┌(・。・)┘♪

7 0
2 years ago
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If 1.8 amp flows through a 40 ohm resistor, the voltage across the resistor is :
GenaCL600 [577]

Answer:

72 volts.

Explanation:

To solve this, we have to use the Ohm's law.

The ohm's law tells us that the voltage drop of a resistor is directly proportional to the current applied to the conductor.

V=I*R

in this case the current is 1.8 amps and the resistor is 40 ohm

V=1.8*40

so

V=72 volts.

5 0
3 years ago
The graph shows a car's velocity over time. During which time period does the car have the greatest acceleration?
Oksana_A [137]

Answer:

Between 0 and 1 seconds (B)

Explanation:

The velocity of the car over time is represented by the line graphed here

the steeper the line, the greater change in velocity that occurred in a given time frame.

The steepest portion of the line is between 0-1 seconds, which means that the greatest rate of change occurred between 0-1 seconds.

(acceleration is the rate of change)

5 0
2 years ago
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According to the first law of thermodynamics, the amount of work done by a heat engine equals the amount of
AleksandrR [38]
C. thermal energy added to the engine minus the waste heat.

The law exemplifies conservation of energy. 
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3 years ago
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A(n) 0.49 kg softball is pitched at a speed of 13 m/s. The batter hits it back directly at the pitcher at a speed of 23 m/s. The
garik1379 [7]
<h2>Impulse  = 4.9 kgm/s</h2>

Explanation:

Impulse is given by change of momentum.

Mass of softball = 0.49 kg

Initial velocity of softball = 13 m/s

Initial momentum = 0.49 x 13 = 6.37 kgm/s

Final velocity of softball = 23 m/s

Final momentum = 0.49 x 23 = 11.27 kgm/s

Change of momentum = Final momentum - Initial momentum

Change of momentum = 11.27 - 6.37

Change of momentum = 4.9 kgm/s

Impulse = Change of momentum

Impulse  = 4.9 kgm/s

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2 years ago
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