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RSB [31]
4 years ago
15

A bar is used to lift a 100-kg block of concrete. The pivot is 1.00m from the block. (a) If the worker pushes down on the other

end of the bar a distance of 2.50m from the pivot, what force (in N) must the worker apply? (b) Find the MA
Physics
1 answer:
Soloha48 [4]4 years ago
7 0
A) From, the principle of moments the clockwise moment is equal to the anticlockwise moments.
 weight of the block × distance from the pivot = Force × distance to the pivot
= 1000× 1 = 2.5 × F
= 2.5 F = 1000
       F =  400 N

b) IMA is an ideal machine's mechanical advantage. They are calculated by dividing the distance over which you apply effort by the distance moved by the load.
In this case; 
IMA = 2.5/1
       = 2.5
The IMA is therefore 2.5
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What is the net force needed to accelerate a 5 kg object at 3 m/s2? Suppose that in this situation you discovered that there is
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The Force need to accelerate the object is by 3 m/s² is 15 N.  Suppose a friction force of 5 N acts on the motion of the object, the force needed to be applied to the object is 20 N

<h3>Force:</h3>

This can be defined as the product of the mass and the acceleration of a body. The S.I unit of force is kgm/s or Newton(N)

To calculate the force needed to accelerate a mass of 5 kg object at 3 m/s² we use the formula below.

Formula:

  • F = ma........ equation 1

Where:

  • F = Net force needed to accelerate the object
  • m = mass of the object
  • a = acceleration of the object

From the question,

Given:

  • m = 5 kg
  • a = 3 m/s²

Substitute these values into equation 1

  • F = 5(3)
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Suppose a frictional force of 5 N acts on the motion, The force applied is

  • F = F'+ma............ Equation 2

Where:

  • F = Frictional force = 5N

Substitute into equation 2

  • F = 5(3)+5
  • F' = 15+5
  • F = 20 N.

Hence, The Force need to accelerate the object is by 3 m/s² is 15 N. Suppose a friction force of 5 N acts on the motion of the object, the force needed to be applied to the object is 20 N

Learn more about force here: brainly.com/question/12970081

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