What is an equation of the line that passes through the points (-4,-1) and (2,8)?
1 answer:
Answer:
y=3/2 x + 5
Step-by-step explanation:
![y = mx + c](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20c)
<em>Firstly, find m (gradient).</em>
m= (y1-y2)/(x1- x2)
m= 8-(-1)/ 2-(-4)
m= 9/ 6
m= 3/2
<em>Please leave gradient in improper fraction if its value is not a whole number.</em>
<em>Now substitute m into the equation:</em>
y= 3/2 x + c
<em>Then substitute a coordinate to find c:</em>
When y= 8, x= 2,
8= 3/2 (2) + c
8= 3 + c
c= 8 - 3 = 5
Thus, the equation of the line is y= 3/2 x + 5.
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Step-by-step explanation:
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Step-by-step explanation:
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5/3 = 1 1/3 segments
hope that helps :)
Answer:
d in (-oo:+oo)
(5/9)*d = 9/10 // - 9/10
(5/9)*d-(9/10) = 0
(5/9)*d-9/10 = 0
5/9*d-9/10 = 0 // + 9/10
5/9*d = 9/10 // : 5/9
d = 9/10/5/9
d = 81/50
d = 81/50
Step-by-step explanation: