2(x+3)= 3x-1
2x+6=3x-1
X=7
Therefore
YM = 7+3= 10
And by definition of midpoint YM=MZ so MZ=10
Answer:
(10, 0)
Step-by-step explanation:
(10, 0) satisfies both of the system equations: 2(10) + 0 = 20 and 4(10) - 0 = 40.
(0, 10) does not.
(4, 2) does not.
(10, -10) does not.
A) <span><span>-2x +</span>5y = 18
B) 6x </span><span><span>+4y </span>= -10
Yes, they are simultaneous equations with one solution.
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Answer:
(4,-3)
Step-by-step explanation:
This is where the 2 lines meet