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Sergeu [11.5K]
3 years ago
15

You need to estimate the floor area of your unusual oval shaped living room from memory you remember that it is longer than wide

r and is about 6m long . So you take it to b rectangular with a witdth of 0.5 m and multiply width by length to get an estimate of 3m why was your estimate not done correctly
Physics
1 answer:
REY [17]3 years ago
4 0

Answer:

Our estimate not done correctly because the width was unrealistic.

Explanation:

Given that,

Length = 6 m

Width = 0.5 m

We need to calculate the area of rectangular floor

Using formula of area

A=l\times w

Where, l = length

w= width

Put the value into the formula

A=6\times0.5

A=3\ m^2

We need to find why this estimate not done correct

Using given data

We can say that,

We assume width was unrealistic.

The length of room is 6 m.

We know that,

1\ m=3.28\ feet

So, the length would be 20 feet.

The width of room is 0.5 m.

The width of room would be 1.64 feet.

So, the area will be

A=20\times1.64

A=32.8\ feet^2

Hence,  Our estimate not done correctly because the width was unrealistic.

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Read 2 more answers
A shot putter shoots a 7.3kg shot from rest to 14m/s in 1.5s. what was the average power?
sweet [91]

Answer: 477W

Explanation:

Given the following :

Mass (m) = 7.3kg

Initial Velocity (u) = 0

Final velocity (v) = 14m/s

time (t) = 1.5s

Power = workdone (W) / time (t)

The workdone can be calculated as the change in kinetic energy (KE) :

Recall ;

KE = 0.5mv^2

Therefore, change in KE is given by:

0.5mv^2 - 0.5mu^2

Change in KE = 0.5(7.3)(14^2) - 0.5(7.3)(0^2)

Change in KE = 715.4J

Therefore ;

Average power = Workdone / time

Workdone = change in KE = 715.4N

Average power = 715.4 / 1.5

Average power = 476.93333 W

= 477W

5 0
4 years ago
Explain why data from at least three seismic stations are needed to locate an earthquake epicenter
Helga [31]
Each station has a circle made of possible epicenters. When you have atleast 3 epicenters you can narrow it down to 1 epicenter and there's that final point. Each station can detect how far away the epicenter was (by transverve body waves). When you only have one seismic station it's impossible to locate an earthquake epicenter.
7 0
3 years ago
WHAT IS THE RISE AND RUN OF THIS GRAPH
777dan777 [17]

Answer:

Explanation:

Comment

Though it is easier to use the origin as one of the points to find the rise over the run, doing the question the more general way will help you with lines that do not go through the origin.

So pick any other two points.

P1(6 , 0.60)

P2(8 , 1.20)

Rise / Run = (y2 - y1)/(x2 - x1)

y2 = 1.20

y1 = 0.90

x2 = 8

x1 = 6

Rise over Run = (1.2 - 0.9) / (8 - 6)

Rise over run = 0.3 / 2  

Technically stated in language, this is the answer. For every 2 pencils the cost goes up 0.3 cents. Carpenters would say it this way.

However in physics it can also be expressed as 0.15 dollars per pencil which is the cost  per pencil.

=========================

Just to show that you will get the same answer using the origin you can do it this way.

y2 = 0.6

y1 = 0

x2 = 4

x1 = 0

rise over run = (0.6 - 0)/ (4 - 0) = 0.6/4 = 0.15 / 1

5 0
4 years ago
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