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Scorpion4ik [409]

3 years ago

15

A student forgets to turn off a 6.00x 10² W block heater of a car when the weather turns warm. If 14 h goes by before he shuts i

t off, how much energy is used by the heater?

1 answer:

Inga [223]3 years ago

3 0

Answer: 8.4 kW•hr

Explanation:

600 W • (14 hr) / (1000 W/kW) = 8.4 kW•hr

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TRUE OR FALSE: In single-slit diffraction, the central band gets thinner as the width of the slit increases.

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3 years ago

A 350-km-long high-voltage transmission line 2.00 cm in diameter carries a steady current of 1,010 A. If the conductor is copper

Masja [62]

Answer:

t = 47 years

Explanation:

To find the number of years in which the electrons cross the complete transmission, you first calculate the drift velocity of the electrons in the transmission line, by using the following formula:

$v_d=\frac{I}{nAq}$ (1)

I: current = 1,010A

A: cross sectional area of the transmission line = π(d/2)^2

d: diameter of the transmission line = 2.00cm = 0.02 m

n: free charge density = 8.50*10^28 electrons/m^3

q: electron's charge = 1.6*10^-19 C

You replace the values of all parameters in the equation (1):

$v_d=\frac{1010A}{(8.50*10^{28}m^{-3})(\pi(0.02m/2)^2)(1.6*10^{-19}C)}\\\\v_d=2.36*10^{-4}\frac{m}{s}$

with this value of the drift velocity you can calculate the time that electrons take in crossing the complete transmission line:

$t=\frac{d}{v_d}=\frac{350km}{2.36*10^{-4}m/s}=\frac{350000m}{2.36*10^{-4}m/s}\\\\t=1,483,050,847\ s$

Finally, you convert this value of the time to years:

$t=1,483,050,847s*\frac{1\ year}{3.154*10^7s}=47\ years$

hence, the electrons take around 47 years to cross the complete transmission line.

7 0

3 years ago