Answer:
new moon
Explanation:
A solar eclipse take place at new moon phase, when the moon passes between the earth and the sun and its shadows fall on the Earth's surface which by definition a solar eclipse.
as per the question the proton is taken from the point of 175 volt to the point of -55 volt.
the work done in case of electric filed is given as
where Vab is the potential difference between two points.
Vab =Va-Vb
=175-[-55]volt
= 230 volt
the charge of proton is 
hence the work done will be-
W=230 volt ×
=368.46
joule [ans]
This is a simple application of Newton's Law of Universal Gravitation.
The force of gravity is inversely proportional to the distance between the two
centers of mass. We don't need to know the mass of earth or the test mass to
solve this, because we'll be setting up a proportionality, which means that all
controlled variables can be expressed as a proportionality constant which will
eventually cancel. <span>
Set up the following proportionality equation from
Newton's Universal Gravitation:
F = k/d²; where k is the constant of proportionality
Plug in values for F and d, making two
equations:
(9.803 N) = k/r²; where r is the radius of earth,
and
(9.792 N) = k/(r+h)²; where h is the height above
sea level.
Divide one by the other, and you get:
9.803 / 9.792 = (r+h)² / r²; the k cancels
Solve for h:
√(9.803 / 9.792) = (r+h) / r
r √(9.803 / 9.792) = r + h
r √(9.803 / 9.792) – r = h
Look up the value for r (radius of earth) and
evaluate:
(6371 km) √(9.803 / 9.792) – (6371 km) = h
<span>h ≈ 3.58 km</span></span>
I think the correct answer would be true. A bonding molecular orbital is of lower energy than the atomic orbitals from which it was formed. Having a lower energy, it makes them more stable than that of the atomic orbitals. They are attracted by nuclei at the same time.
Answer:
Explanation:
Let assume that 100 kg of the compound is tested. The quantity of kilomoles for each element are, respectively:
Ratio of kilomoles oxygen to kilomole nitrogen is:
It means that exists 1.499 kilomole oxygen for each kilomole nitrogen.
The empirical formula for the compound is:
