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2 years ago

-56.72 divided by -8

Mathematics

2 answers:

katrin2010 [14]2 years ago

8 0

Answer:

7.09

Step-by-step explanation:

Alex17521 [72]2 years ago

3 0

Answer:

The awnser to -56.72 divided by -8 is +7.09 because when a negative is divided by a negative the wanser is always posotive

Step-by-step explanation:

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Deposits $10 in an account that earns an interest rate of 5% compounded annually. What is the balance in the account at the end

d1i1m1o1n [39]

Compound Interest is calculated on the initial payment and also on the interest of previous periods.

So after 1 year w/ 5% interest, $10 -> $10*1.05 = $10.5
after 2 year, the total becomes $10.5*1.05 = $11.025

formula to calculate is 10*(1.05)^50 = $114.67

ans is A

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2 years ago

Rex weighed 80 pounds a year ago. Now he weighs 92 pounds. What is the percent increase in his weight?

Anna11 [10]

So increased weight = 92-80 = 12

so ℅ = 12×100/80 = 15

so his weight is increased by 15℅ !!

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2 years ago

On a number line, point D is at -3, and point E is at 6. The point F lies on DE. The ratio of DF to FE is 2:3. Where does point

expeople1 [14]

Answer: point F is at 0.6 on the number line

=============================================================

Explanation:

The ratio 2:3 scales up to 2x:3x for some positive real number x.

This means the distance from D to F is 2x units, and the distance from F to E is 3x units. Combine those two smaller distances to get 2x+3x = 5x to represent the full distance from D to E.

D is at -3 and E is at 6. This is a distance of 9 units since |-3-6| = |-9| = 9

Set this equal to the 5x from earlier and solve

5x = 9

x = 9/5

x = 1.8

This leads to 2x = 2*1.8 = 3.6

Therefore, we'll move 3.6 units from -3 to -3+3.6 = 0.6 which is the location of point F on the number line.

Notice that from 0.6 to 6 is 5.4 units and that 3x = 3*1.8 = 5.4 matches up to help confirm the answer.

5 0

2 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

2 years ago

How many solutions does an equation have when you isolate the variable and it equals a constant?

OLEGan [10]

1 solution is available when variable equals a constant.

Answer: Option B.

Explanation:

You will be able to determine if an equation has one solution (which is when one variable equals one number), or if it has no solution (the two sides of the equation are not equal to each other) or infinite solutions (the two sides of the equation are identical).

The ordered pair that is the solution of both equations is the solution of the system. A system of two linear equations can have one solution, an infinite number of solutions, or no solution. If a consistent system has exactly one solution, it is independent.

3 0

3 years ago