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klasskru [66]
3 years ago
11

Round 0.076 to the nearest tenth. 0.07 0.08 0.076 0.1

Mathematics
2 answers:
Sladkaya [172]3 years ago
8 0
The answers is 0.08 because the 6 in 0.076 is over five so you round the number up 
Dmitry [639]3 years ago
7 0
The answer would be 0.1 because the first decimal place is tenths, then hundredths, then thousandths, etc.
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PLEASE HELP!!
valkas [14]
A) Here, sum of two non-adjacent angles: 52 + 25 = 77
Now, ∠3 = 180 - 77   [ sum of all angles in a triangle is 180 ]
so, ∠3 = 103

Now, ∠3 + ∠4 = 180  [ Supplementary angles ]
So, ∠4 = 180 - ∠3
∠4 = 180 - 103 = 77
∠4 = 77 [ which is sum of two non-adjacent angles ]

....Hence proved.

b) m∠4 = 77 
[ Solved in previous section ]

Hope this helps!

4 0
3 years ago
Read 2 more answers
You obtain a simple interest loan from National City for $2,500 at 7.5% for 5 years. Find the amount of interest on the loan
natita [175]

Answer:

$937.50

Step-by-step explanation:

interest (I) is calculated as

I = PRT

where P is the principal ( amount borrowed ), R is the rate of interest and T is the time in years

here P = $2500, R = 7.5 and T = 5

I = $2500 × \frac{7.5}{100} × 5 = 25 × 7.5 × 5 = $937.50


5 0
3 years ago
Simplify 12st over 4t
soldier1979 [14.2K]
\huge{\frac{12st}{4t}=\frac{12s}{4}=\boxed{3s}
7 0
2 years ago
Part A
DIA [1.3K]

Answer:

is there a figure for this question?

5 0
3 years ago
Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from
Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that P = 3000, r = 0.16, n = 1

So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 3000(1 + \frac{0.16}{1})^{t}

A(t) = 3000(1.16)^{t}

(a) Find the amount in the account at the end of 1 year.

This is A(1).

A(t) = 3000(1.16)^{t}

A(1) = 3000(1.16)^{1} = 3480

(b) Find the amount in the account at the end of 2 years.

This is A(2).

A(2) = 3000(1.16)^{2} = 4036.8

4 0
3 years ago
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