Answer:
<h2>7/130</h2>
Step-by-step explanation:
Using set notation to answer the question. let:
n(U) be the total people in a sport centre =130
n(G) be number of people that use the gym. = 76
n(P) be number of people that use the swimming pool. = 60
n(T) be number of people that use the track = 32
n(G∩P) be number of people that uses the gym and the pool = 23
n(P∩T) be number of people that uses the pool and the track = 8
n(G∩T) be number of people that uses the gym and the track = 320
n(G∩P∩T) be number of people that uses all three facilities = 6
Using the relationship below;
n(U)= n(GUPUT)+n(GUPUT)'
where n(GUPUT)' is the number of people that doesn't use any facility.
Before we can get that, we need to know n(GUPUT) using the formula;
n(GUPUT) = n(G) + n(P)+n(T)-n(G∩P)-n(P∩T)-n(G∩T)+n(G∩P∩T)
n(GUPUT) = 76+60+32-23-8-20+6
n(GUPUT) = 123
n(GUPUT)' = n(U)- n(GUPUT)
n(GUPUT)' = 130 - 123
n(GUPUT)' = 7
This means that 7 person doesn't use any facility.
Probability that a person selected at random doesn't use any facility = n(GUPUT)' /n(U) = 7/130
