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3 years ago

Can someone solve and explain

Mathematics

1 answer:

S_A_V [24]3 years ago

6 0

The answer is F.30
Explanation: If we do guess and check, if we multiply the ratios by 10, it would be 30:40:50, which doesn’t add up to 180 degrees. if we multiply the ratios by 20, It would be 60:80:100, which also doesn’t add up to 180 degrees. How about we multiply the ratios by 15? It would be 45:60:75, which does add up to 180! The difference between x and z is 30, so the answer is F.30

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3 years ago

If 3m - n = 11, then m =

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Answer:

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Step-by-step explanation:

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3 years ago

The amounts of time employees at a large corporation work each day are normally distributed, with a mean of 7.5 hours and a stan

Ber [7]

Answer:

When sample size increases from n = 23 to n = 35, the mean of the distribution of sample means remains same but the standard deviation of the distribution of sample means decreases from 0.073 to 0.059.

Step-by-step explanation:

We are given the amounts of time employees at a large corporation work each day are normally distributed, with a mean of 7.5 hours and a standard deviation of 0.35 hour.

Random samples of size 23 and 35 are drawn from the population and the mean of each sample is determined.

Here, $\mu$ = population mean = 7.5 hours

$\sigma$ = population standard deviation = 0.35 hour

<u><em>Let </em></u> $\bar X$ <u><em> = sample mean</em></u>

(a) The random samples of size of n = 23 is drawn from the population;

So, mean of the distribution of sample means = $\mu$ = 7.5 hours

Standard deviation for the distribution of sample means is given by;

s = $\frac{\sigma}{\sqrt{n} }$ = $\frac{0.35}{23}$ = 0.073

(b) The random samples of size of n = 35 is drawn from the population;

So, mean of the distribution of sample means = $\mu$ = 7.5 hours

Standard deviation for the distribution of sample means is given by;

s = $\frac{\sigma}{\sqrt{n} }$ = $} \frac{0.35}{\sqrt{35} }$ = 0.059

(c) So, as we can see that when sample size increases from n = 23 to n = 35, the mean of the distribution of sample means remains same but the standard deviation of the distribution of sample means decreases from 0.073 to 0.059.

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3 years ago

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Now for calculating fertilizer rate of application in pots, you calculate according to soil weigh as you correctly indicated 2.2 M Kg/ha. You don't have to weigh the soil, just use the bulk density to calculate weigh from volume. Forget about space in pot experiment. you will have a lot of problems since pots have different shapes and forms!

Another recommandation mix soil and fertilizers for each treatment for the number of replicate pots. If you are using 5 replicates pot of 2 Kg soil/ pot, mix the fertilizers you want to apply to the 5 pots with 10 Kg of soil and after mixing well (preferably mechanically) distribute the same volume of soil in each one of the 5 pots.

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You might also consider fractionating you nitrogen source if it will be leached.

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Wishing you a lot of success in your work

<h3>hope it's help you </h3><h3>plz mark as brain list.......!!!!!!!!!!!!!!!!</h3>

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3 years ago

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Z-2.3 = 0.46 what is z<br> Please help me

ddd [48]

Answer:

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Step-by-step explanation:

Firstly you must realise that Z - 2.3 = 0.46

Therfore this means you must 2.3 to 0.46 to get Z

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5 0

3 years ago

Read 2 more answers