The value of 2pg in the given population is 0.432
<u>Explanation:</u>
Given:
C is normal
c is curly wings
So the homozygous dominant condition would be CC
Heterozygous condition would be Cc
Recessive condition would be cc
According to Hardy Weinberg principle,
p² + 2pq + q² = 1
and
p + q = 1
Here,
q² = cc = 100
q² = 100 / 1000
q = √0.1
q = 0.316
So,
p + q = 1
p + 0.316 = 1
p = 0.684
Thus, 2pq would be:
![= 2 X (0.684) X (0.316)\\\\= 0.432](https://tex.z-dn.net/?f=%3D%202%20X%20%280.684%29%20X%20%280.316%29%5C%5C%5C%5C%3D%200.432)
Therefore, the value of 2pg in the given population is 0.432