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taurus [48]
3 years ago
14

Why is gold foil used on sculptures

Chemistry
2 answers:
Troyanec [42]3 years ago
7 0
Its to give it appeal painting the same would discolour quicker.
Aleonysh [2.5K]3 years ago
5 0

The gold leaf (not foil) is to give a sculpture or a painting appeal. Without it, it would discolour quicker.The gold leaf can be easily removed if needed to be.

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How many mol of hydrogen are needed to double the volume occupied by 0.34 mol of hydrogen,
natima [27]

Answer:

0.68

Explanation:

Number of moles is directly propotionalto the volume at standard condition.

6 0
3 years ago
Abbreviated electron configuration for tellurium
Zinaida [17]

Answer:

The ground state electron configuration of ground state gaseous neutral tellurium is [Kr]. 4d10.

4 0
2 years ago
How many carbon atoms are there in one molecule of CH3FO?
Vlad1618 [11]

Answer:

Brainliest pls

Explanation:

1 mole of a substance contains Avagadro’s number of particles,

i.e. 6.023*10^23

By unitary method,

5 moles of oxygen contains 5 times the Avagadro’s number of particles

i.e. 5* (6.023*10^23) = 3.0115*10^24 number of particles.

Now, the further answer depends on what particles the question concentrates on.

If number of atoms are asked , the above answer must be multiplied by 2, because oxygen is a diatomic gas and each atom contributes to be a particle.

therefore, 5 moles of oxygen has 6.023*10^24 atoms.

If number of molecules asked, the above answer is directly written...

8 0
2 years ago
A first-order reaction is 45% complete at the end of 43 minutes. What is the length of the half-life of this reaction
shtirl [24]

The half-life of the reaction is 50 minutes

Data;

  • Time = 43 minutes
  • Type of reaction = first order
  • Amount of Completion = 45%

<h3>Reaction Constant</h3>

Let the initial concentration of the reaction be X_0

The reactant left = (1 - 0.45) X_0 = 0.55 X_0 = X

For a first order reaction

\ln(\frac{x}{x_o}) = -kt\\ k = \frac{1}{t}\ln (\frac{x_o}{x}) \\ k = \frac{1}{43}\ln (\frac{x_o}{0.55_o})\\ k = 0.013903 min^-^1

<h3>Half Life </h3>

The half-life of a reaction is said to be the time required for the initial amount of the reactant to reach half it's original size.

x = \frac{x_o}{2} \\t = t_\frac{1}{2} \\t_\frac{1}{2} = \frac{1}{k}\ln(\frac{x_o}{x_o/2})\\

Substitute the values

t_\frac{1}{2} = \frac{1}{k}\ln(2)=\frac{0.6931}{0.013903}\\t_\frac{1}{2}= 49.85 min = 50 min

The half-life of the reaction is 50 minutes

Learn more on half-life of a first order reaction here;

brainly.com/question/14936355

4 0
2 years ago
The precautions that must be taken when carrying out experiments with hydrogen​
vodka [1.7K]

Answer:

Never smoke near a place where hydrogen is generated or being used. Remove all possible sources of flame and sparks. Hydrogen should only be generated and used in a well ventilated out door area. Precautions must be taken to remove all possibilities of fire or explosion.

3 0
3 years ago
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