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taurus [48]
4 years ago
14

Why is gold foil used on sculptures

Chemistry
2 answers:
Troyanec [42]4 years ago
7 0
Its to give it appeal painting the same would discolour quicker.
Aleonysh [2.5K]4 years ago
5 0

The gold leaf (not foil) is to give a sculpture or a painting appeal. Without it, it would discolour quicker.The gold leaf can be easily removed if needed to be.

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How many grams are in 2.3 x 10^ -4 moles of calcium phosphate? ​
Yanka [14]

Answer:

Mass = 713.4 ×10⁻⁴ g

Explanation:

Given data:

Number of moles of calcium phosphate = 2.3×10⁻⁴ mol

Mass of calcium phosphate = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of calcium phosphate is 310.18 g/mol

by putting values,

2.3×10⁻⁴ mol = mass / 310.18 g/mol

Mass = 2.3×10⁻⁴ mol × 310.18 g/mol

Mass = 713.4 ×10⁻⁴ g

3 0
3 years ago
Draw both major organic product(s) that are obtained when 4-chloro-2-methyltoluene is treated with sodium amide followed by trea
victus00 [196]

Answer:

I attached the answer as an image. I also drew in the two most acidic hydrogens.

Explanation:

This goes through the 'benzyne' intermediate, meaning it does an E2-looking reaction by expelling a leaving group (chloride) from the adjacent part of the ring using the amide as a strong base. The triple-bonded benzyne has absurd bond angle strain, and is vulnerable to a good nucleophile like an amide ion, and the resultant sp2 anion is then reprotonated by the acid. I didn't draw in the acid-base reaction in step one, or the spectator ion (sodium).

5 0
3 years ago
Calculate how many grams of hydrogen can be burned if 40. liters of oxygen at 200. k and 1.0 atm. show work pls.
Wittaler [7]

The grams of hydrogen gas can be burned if 40. liters of oxygen at 200. k and 1.0 atm is 4.88 grams.

<h3>How do we calculate grams from moles?</h3>

Grams (W) of any substance will be calculated by using their moles (n) through the following equation:

  • n = W/M, where

M = molar mass

And moles of the gas will be calculated by using the ideal gas equation as:

  • PV = nRT, where

P = pressure = 1atm

V = volume = 40L

n = moles = ?

R = universal gas constant = 0.082 L.atm / K.mol

T = temperature = 200K

On putting these values on the above equation, we get

n = (1)(40) / (0.082)(200) = 2.439 = 2.44 moles

  • Now grams of hydrogen gas will be calculated by using the first equation as:

W = (2.44mol)(2g/mol) = 4.88g

Hence required mass of hydrogen gas is 4.88g.

To know more about ideal gas equation, visit the below link:

brainly.com/question/15046679

#SPJ1

7 0
3 years ago
Relationship between the variables of Pressure and Temperature of a gas?
pychu [463]

Answer:

The pressure of a given amount of gas is directly proportional to iys absolute temperature provided that that the volume does not change

7 0
3 years ago
A is more linear than wich
bekas [8.4K]
You should put a picture or finish the question
4 0
4 years ago
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