<span>Lemon juice has more acid because of its density and it contains more sodium.</span>
Answer:
- Neutral solutions: concentration of hydronium equals the concentration of hydroxide.
- Acid solutions: concentration of hydronium is greater than the concentration of hydroxide.
- Basic solutions concentration of hydronium is lower than the concentration of hydroxide.
Explanation:
Hello,
It is widely known that the pH of water is 7, therefore the pOH of water is also 7 based on:

In such a way, we can compute the concentration of hydronium and hydroxide ions as shown below:
![pH=-log([H^+])\\](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29%5C%5C)
![[H^+]=10^{-pH}=10^{-7}=1x10^{-7}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-pH%7D%3D10%5E%7B-7%7D%3D1x10%5E%7B-7%7DM)
![pOH=-log([OH^-])](https://tex.z-dn.net/?f=pOH%3D-log%28%5BOH%5E-%5D%29)
![[OH^-]=10^{-pOH}=10^{-7}=1x10^{-7}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E%7B-pOH%7D%3D10%5E%7B-7%7D%3D1x10%5E%7B-7%7DM)
Thus, we notice that the relationship between the concentration of the hydronium is equal for water or neutral solutions. Moreover, if we talk about acid solutions, pH<OH therefore the concentration of hydronium is greater than the concentration of hydroxide. On the other hand if we talk about basic solutions, pH>OH therefore the concentration of hydronium is lower than the concentration of hydroxide.
Best regards.
The answer is most likely nonmetals. :)
The answer is Helium Nucleus. The alpha particle is what is emitted.
The activity of the sample when it was shipped from the manufacturer is 4.54 mCi
<h3>How to determine the number of half-lives that has elapsed </h3>
From the question given above, the following data were obtained:
- Time (t) = 48 hours
- Half-life (t½) = 14.28 days = 14.28 × 24 = 342.72 hours
- Number of half-lives (n) =?
n = t / t½
n = 48 / 342.72
n = 0.14
<h3>How to determine the activity of the sample during shipping </h3>
- Number of half-lives (n) = 0.14
- Original activity (N₀) = 5.0 mCi
- Activity remaining (N) =?
N = N₀ / 2ⁿ
N = 5 / 2^0.14
N = 4.54 mCi
Thus, the activity of the sample during shipping is 4.54 mCi
Learn more about half life:
brainly.com/question/2674699