Answer: New pressure inside the flask would be 148.8 kPa.
Explanation: The combined gas law equation is given by:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
As the flask is a closed flask, so the volume remains constant. Temperature is constant also.
So, the relation between pressure and number of moles becomes
![P=n\\or\\\frac{P}{n}=constant](https://tex.z-dn.net/?f=P%3Dn%5C%5Cor%5C%5C%5Cfrac%7BP%7D%7Bn%7D%3Dconstant)
![\frac{P_1}{n_1}=\frac{P_2}{n_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1%7D%7Bn_1%7D%3D%5Cfrac%7BP_2%7D%7Bn_2%7D)
![P_1=93kPa\\n_1=5\text{ puffs}](https://tex.z-dn.net/?f=P_1%3D93kPa%5C%5Cn_1%3D5%5Ctext%7B%20puffs%7D)
- Final conditions: When additional 3 puffs of air is added
![P_2=?kPa\\n_2=8\text{ puffs}](https://tex.z-dn.net/?f=P_2%3D%3FkPa%5C%5Cn_2%3D8%5Ctext%7B%20puffs%7D)
Putting the values, in above equation, we get
![\frac{93}{5}=\frac{P_2}{8}\\P_2=148.8kPa](https://tex.z-dn.net/?f=%5Cfrac%7B93%7D%7B5%7D%3D%5Cfrac%7BP_2%7D%7B8%7D%5C%5CP_2%3D148.8kPa)
155,500
I did this to the best of my ability. I have a hard time comprehending things sometimes so I’m so so so sorry if it’s wrong
The answer is A lithium sulfite