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IgorLugansk [536]
3 years ago
10

3. The scientific study of how organisms are classified is called _____.

Chemistry
1 answer:
Vilka [71]3 years ago
3 0
Hey mate!

Taxonomy is the <span>study of classification of organisms. Therefore, your answer is A.

Hope this helps!</span>
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La masse et volume. S'il vous plaît repondre aux questions 2, 3, et 4.​
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Answer:

Bonjour! Je me demandais si vous pouviez s’il vous plaît traduire vos questions en anglais afin que je puisse les résoudre. J’utilise un traducteur en ce moment pour vous dire votre réponse dans Français. Je suis désolé si vous ne pouvez pas traduire cela. Bonne journée!

Explanation:

3 0
3 years ago
Identify the intermolecular forces present in each of these substances nh3 hcl co co2
nasty-shy [4]
Intermolecular forces are forces of interaction that are operative between two different molecules. They are of follow types
1) Dipole- dipole interaction
2) Hydrogen bonds
3) vander Waal's forces

Depending upon the polarity and constitution molecule above forces are operable.

for instance, in case of ammonia, Hydrogen bonds exist because hydrogen atom is attached to electronegative element i.e. N

HCl and CO are polar molecules, so dipole-dipole interaction is operative in these molecules.

Finally in case of CO2, vander Waal's forces of interaction is operable because it is a non-polar molecule.

4 0
3 years ago
Read 2 more answers
Naoki's bicycle has a mass of 10 kg. If Naoki sits on her bicycle and starts pedaling with a force of 168 N, causing an accelera
White raven [17]

Answer:

50 kg

Explanation:

Data:

Mass of bicycle = 10 kg

                       F = 168 N

                       a = 2.8 m/s²

Calculation:

                     F = ma     Divide each side by m, Then

                 m = F/a

                     = 168/2.8

                      = 60 kg

                 m = mass of bicycle + Naoki's mass. Then

                60 = 10 + Naoki's mass     Subtract 10 from each side

Naoki's mass = 50 kg

3 0
3 years ago
What is a trade-off? <br><br><br><br><br> Don't mind the highlighted yellow circle
kirill [66]

Answer:

a new scientific discovery that benefits the environment

5 0
3 years ago
An analytical chemist is titrating of a solution of propionic acid with a solution of 224.9 ml of a 0.6100M solution of propioni
Svetllana [295]

<u>Answer:</u> The pH of acid solution is 4.58

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}    .....(1)

  • <u>For KOH:</u>

Molarity of KOH solution = 1.1000 M

Volume of solution = 41.04 mL

Putting values in equation 1, we get:

1.1000M=\frac{\text{Moles of KOH}\times 1000}{41.04}\\\\\text{Moles of KOH}=\frac{1.1000\times 41.04}{1000}=0.04514mol

  • <u>For propanoic acid:</u>

Molarity of propanoic acid solution = 0.6100 M

Volume of solution = 224.9 mL

Putting values in equation 1, we get:

0.6100M=\frac{\text{Moles of propanoic acid}\times 1000}{224.9}\\\\\text{Moles of propanoic acid}=\frac{0.6100\times 224.9}{1000}=0.1372mol

The chemical reaction for propanoic acid and KOH follows the equation:

                 C_2H_5COOH+KOH\rightarrow C_2H_5COOK+H_2O

<u>Initial:</u>          0.1372         0.04514  

<u>Final:</u>           0.09206          -                0.04514

Total volume of solution = [224.9 + 41.04] mL = 265.94 mL = 0.26594 L     (Conversion factor:  1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{salt}]}{[acid]})

pH=pK_a+\log(\frac{[C_2H_5COOK]}{[C_2H_5COOH]})

We are given:  

pK_a = negative logarithm of acid dissociation constant of propanoic acid = 4.89

[C_2H_5COOK]=\frac{0.04514}{0.26594}

[C_2H_5COOH]=\frac{0.09206}{0.26594}

pH = ?  

Putting values in above equation, we get:

pH=4.89+\log(\frac{(0.04514/0.26594)}{(0.09206/0.26594)})\\\\pH=4.58

Hence, the pH of acid solution is 4.58

7 0
4 years ago
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