Answer: While I don’t have the picture to actually know the answer I will explain how to get it.
Step-by-step explanation:
1. If the shapes are on a grid count the amount of grid squares that are located between each end point of the shape. If it’s not on a grid use a ruler to measure the side lengths. You will need to find out the side amounts for both shapes L and S.
2. From there if the L shape is SMALLER than the S shape, then take the S shape’s sides and divide it by the L shape’s sides, and whatever number you get from each of your division problems will be your scale factor. BUT If the L shape is BIGGER than the S shape then easiest way to find out your scale factor is to take the last scale factor you got and convert it into a fraction. For example, if you got 3 then it would be 1/3. Hope this helped!
Answer:
One approach to this problem is to obtain the graph for the given equation.
We need to find every intersection those functions have with the axis 'x' and 'y'
starting with g(x)
g(x=0)=0-3, first point (0,-3) it iis the crossing point with 'x' axis
g(x)=0=x-3, second point (3,0) it iis the crossing point with 'y' axis
Lets do the same for f(x)
g(x=0)=0, this leads to the first point (0,0) it iis the crossing point with 'x' axis and also, with the 'y' axis
We dont need to find any other, since always y=x
By plotting we have the attached picture
Now you can see that g(x) differs from its parent function in that is shifted 3 units to the right, and also 3 units down.
Step-by-step explanation:
Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
Answer:
BC + CD = BD
hope it helps
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