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IrinaVladis [17]
3 years ago
15

Which pair of slopes could represent perpendicular lines?

Mathematics
1 answer:
mixer [17]3 years ago
3 0
The answer is <span>-3/4 , 4/3 (just look at the lesson!!)</span>
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Help ME! solve for ∠K.
Ainat [17]

Answer:

45

Step-by-step explanation:

Every Triangle has 180 degrees.

x + 8x + 3x = 180

12x = 180

x = 180/12

x = 15

Angle K = 3x

K = 3 * 15

K = 45

3 0
3 years ago
The distance by rail from Leicester to Londonis 100 miles.
Zarrin [17]

The arrival time in london of a train that leaves Leicester to london at 11:50 A.M is 13:05 pm.

To calculate the arrival time in london of a train that leaves Leicester to london at 11:50 A.M, use use the formula below.

Formula:

  • Ta = [(d/s)+11:50]....... Equation 1

Where:

  • Ta = Arrival time
  • d = distance from Leicester to London
  • s = Speed

From the question,

Given:

  • d = 100 miles
  • s = 80 mph

Substitute these values into equation 1

  • Ta = [(100/80)+11:50]
  • Ta = 1.25h+11:50
  • Ta = 1 hours 15 minutes +11:50
  • Ta = 13:05 pm

Hence, the arrival time in london of a train that leaves Leicester to london at 11:50 A.M is 13:05 pm.

Learn more about time here: brainly.com/question/4931057

5 0
2 years ago
busy bees charter school is going to celebrate the end of the school year at an amusement park. Student tickets at the amusement
igor_vitrenko [27]

Answer:

Step-by-step explanation:

6 0
3 years ago
Which relation is a function? Select all that apply.
sineoko [7]
The first 3 are functions as their x coordinate (number on the left side of the parentheses) is not repeated in any of the other parentheses
4 0
3 years ago
Read 2 more answers
in the given figure, AB//PQ//CD. AB = x units. CD = y units and PQ = z unites. Prove that 1/x + 1/y = 1/z
Arlecino [84]
12. ∆ABD is similar to ∆PQD, so
   QD/z = BD/x
Likewise ∆CDB is similar to ∆PQB, so
   QB/z = BD/y

Since QD + QB = BD, you have
   QD/z + QB/z = BD/x + BD/y
   BD/z = BD/x + BD/y
Dividing by BD gives the desired result:
   1/x + 1/y = 1/z


13. Triangles ABD, BCD, and ACB are all similar. This means
   AB/AC = AD/AB
   AB² = AC×AD = (4 cm)×(9 cm)
   AB² = 36 cm²
   AB = 6 cm
and
   BD/CD = AD/BD
   BD² = CD×AD = (5 cm)×(4 cm)
   BD² = 20 cm²
   BD = 2√5 cm
7 0
3 years ago
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