Answer:
the angle of elevation of the sun is 
Step-by-step explanation:
Let's make a diagram of the tree, ground and inclination of the rays of the sun, so we understand what right angle triangle we have. Please see the attached image.
Notice that our unknown is the angle
, and that we know the size of the side opposite to it, and of the side adjacent to it. Therefore the most convenient trigonometric formula to use is the tangent of the angle because:

The equation that represents the <em>sinusoidal</em> function is
,
.
<h3>Procedure - Determination of an appropriate function based on given information</h3>
In this question we must find an appropriate model for a <em>periodic</em> function based on the information from statement. <em>Sinusoidal</em> functions are the most typical functions which intersects a midline (
) and has both a maximum (
) and a minimum (
).
Sinusoidal functions have in most cases the following form:
(1)
Where:
- Angular frequency
- Angular phase, in radians.
If we know that
,
,
,
and
, then the sinusoidal function is:
(2)
(3)
The resulting system is:
(2b)
(3b)
By applying <em>inverse trigonometric </em>functions we have that:
,
(2c)
,
(3c)
And we proceed to solve this system:


,

By (2c):



The equation that represents the <em>sinusoidal</em> function is
,
. 
To learn more on functions, we kindly invite to check this verified question: brainly.com/question/5245372
One and three eighths. Or eleven eighths.
Question 1:
For this case we must factor the following expression:

We must find two numbers that when multiplied result in -24 and when added together result in 2. These numbers are: 6 and -4.

Thus, we factor:

The roots are:

Answer:
Option C
Question 2:
For this case we have that by definition, the area of a rectangle is given by:

Where:
w: Is the width of the rectangle
l: is the length of the rectangle
According to the statement we have:

Substituting:

Where:

The solution:

We have two roots:

We choose the second value (the positive), when rounding is 
Answer:
Option A