You can reduce the percentages to fractions:


So, we have


Answer:
24/49
Step-by-step explanation:
Let's add the terms and see if there's a pattern

Suppose we say the sum of n terms is (n/(2n+1)), the next term in the series will be 1/((2n+1)(2n+3)) and adding that to the presumed sum gives ...

Then it appears the sum of n terms is (n/(2n+1)). So, the sum of 24 terms is ...

Answer:
the second option!
Step-by-step explanation:
hope this helps! will appreciate brainliest!
What do you need help with
D., Because 29 x 15 is 435 but if you throw the .07 in the mix you'll have 436.05 which breaks even.