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3 years ago

What is the messer of x

Mathematics

2 answers:

Rasek [7]3 years ago

5 0

If you subtract 90 - 26 you would get 64

Answer: B

cupoosta [38]3 years ago

4 0

The second one, B 64

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B. What is the related division equation to 23x9

almond37 [142]

Answer:

The Answer is gonna be :207

6 0

3 years ago

12) The product of three integers x, x + 2, and x – 5 is 240? What are the integers?

Alexxx [7]

Answer:

Step-by-step explanation:

x(x+2) (x-5) -240

put that on a graph calculator and the x=8

x=8

x+2=10

x-5=3

7 0

3 years ago

Please help!! ALgebra 2 I will be h=giving out extra points the the brainiest answers

Arte-miy333 [17]

Answer:

Step by Step Explanation

4 0

3 years ago

What is the difference?

Ganezh [65]

Answer:

$\frac{x^2+4x-1}{x(x+2)}$

Step-by-step explanation:

Given

$\frac{x+5}{x+2}$ - $\frac{x+1}{x^2+2x}$ ← factor denominator

= $\frac{x+5}{x+2}$ - $\frac{x+1}{x(x+2)}$

We require the fractions to have a common denominator.

Multiply numerator/denominator of first fraction by x

= $\frac{x(x+5)}{x(x+2)}$ - $\frac{x+1}{x(x+2)}$

Subtract terms on numerator leaving the common denominator

= $\frac{x^2+5x-x-1}{x(x+2)}$

= $\frac{x^2+4x-1}{x(x+2)}$

7 0

3 years ago

Rewrite the function by completing the square. 4x^2-4x+1=0

andrey2020 [161]

Do in completing the square method.

${4x}^{2} - 4x + 1 = 0 \\ 4x^{2}-4x=-1 \\ \frac{4x^{2}-4x}{4}=\frac{-1}{4} \\ x^{2}+\frac{-4}{4}x=\frac{-1}{4} \\ x^{2}-x=\frac{-1}{4} \\ x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-\frac{1}{4}+\left(-\frac{1}{2}\right)^{2} \\ x^{2}-x+\frac{1}{4}=\frac{-1+1}{4} \\ x^{2}-x+\frac{1}{4}=0 \\ \left(x-\frac{1}{2}\right)^{2}=0 \\ \sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{0}$

Now simplify.

$x-\frac{1}{2}=0 \\ x-\frac{1}{2}=0 \\ \\ \rightarrow \: x=\frac{1}{2} \\ \rightarrow \: x=\frac{1}{2}$

So, answer is..

$\boxed{x=\frac{1}{2} }$

Now rewrite the equation.

$4 x ^ { 2 } - 4 x + 1 = 0 \\ \boxed{4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0 }$

Verification :-

$4 x ^ { 2 } - 4 x + 1 = 0 \\ 4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0 \\ 1-4\times \left(\frac{1}{2}\right)+1=0 \\ 1-\frac{4}{2}+1=0 \\ 1-2+1=0 \\ -1+1=0 \\ \underline{ 0 = 0} \: \\ \dashrightarrow \text{true}$

3 0

3 years ago