Answer:
P=41.72
Step-by-step explanation:
S=ACxDB/2
81.7=8.6xDB/2
81.7=4.3xDB|:4.3
19(mm)=DB
DO=19/2=9.5
OC=8.6/2=4.3
(O is the center of the rhombus, where two diagonals meet)
a²+b²=c² (DO²+OC²=DC²)
9.5²+4.3²=c²
90.25+18,49=c²
√108,74=√c²
c≈10.43
P=4c
P=4x10.43
P=41.72
Hope it helps:)
Answer:
Step-by-step explanation:
Given that the figure is made up of portion of a square and a semicircle, we have;
BC ≅ AB = 6 cm
The area of semicircle BC with radius BC/2 = 3 is 1/2×π×r² = 1/2×π×3² = 4.5·π cm²
Triangle ABC = 1/2 × Area of square from which ABC is cut
The area of triangle ABC = 1/2×Base ×Height = 1/2×AB×BC = 1/2×6×6 = 18 cm²
The area of the figure = The area of semicircle BC + The area of triangle ABC
The area of the figure = 4.5·π cm² + 18 cm² = 
.
Answer:
• No
• Yes
• Yes
• No
Step-by-step explanation:
To determine if the 4 given values of y are solutions to the inequality, start by solving the inequality. Solving an inequality is just like that of an equation, except that the direction of the sign changes when the inequality is divided by a negative number.
-2y +7≤ -5
Subtract 7 on both sides:
-2y≤ -5 -7
-2y≤ -12
Divide by -2 on both sides:
y≥ 6
This means that the solution can be 6 or greater than 6.
-10 and 3 are smaller than 6 and are not a solutions, while 7 and 6 satisfies the inequality and are therefore solutions.
_______
Alternatively, we can also substitute each value of y into the inequality and check if the value is less than or equal to -5.
Here's an example to check if -10 is a solution.
-2y +7≤ -5
When y= -10,
-2y +7
= -2(-10) +7
= 20 +7
= 27
Since 27 is greater than 5, it is <u>not</u> a solution to the inequality.
It’s 2/15
It’s just 2x1 and 3x5
