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kati45 [8]
3 years ago
7

What is the mass of 8.12 × 10^23 molecules of CO2 gas? (Atomic mass of carbon = 12.011 u; oxygen = 15.999 u.)

Chemistry
1 answer:
amid [387]3 years ago
4 0

Answer:

m=59.3gCO_2

Explanation:

Hello,

In this case, the first step is to compute the molar mass of carbon dioxide as shown below, considering it has one carbon atom and two oxygen atoms:

M=12.011g/mol+2*15.999g/mol\\\\M=44.009g/mol

It is important to notice it is the mass in one mole of such compound. Afterwards, we need to use the Avogadro's number to compute the how many moles are in the given molecules of carbon dioxide as shown below:

mol=8.12x10^{23}molec*\frac{1mol}{6.022x10^{23}molec} =1.35mol

Finally, the mass by using the molar mass:

m=1.35mol*\frac{44.009g}{1mol} \\\\m=59.3gCO_2

Best regards.

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gravity, magnetic, electrostatic

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3 years ago
Oxalic+acid+is+a+toxic+substance+used+by+laundries+to+remove+rust+stains.+its+composition+is+26.7%+c,+2.2%+h,+and+71.1%+o+(by+ma
Anettt [7]

The molecular formula of a compound is C₂H₂O₄.

Take 100 grams of compound:

1) ω(C) = 26.7% ÷ 100% = 0.267

m(C) = ω(C) × m(compound)

m(C) = 0.267 × 100 g.

m(C) = 26.7 g.

n(C) = m(C) ÷ M(C).

n(C) = 26.7 g ÷ 12 g/mol.

n(C) = 2.22 mol; amount of carbon

2) ω(H) = 2.2 % ÷ 100% = 0.022

m(H) = 0.022 × 100 g.

m(H) = 2.2 g.

n(H) = 2.2 g ÷ 1 g/mol.

n(H) = 2.2 mol; amount of hydrogen

3) ω(O) = 71.1 % ÷ 100%.

ω(O) = 0.711

m(O) = 0.711 × 100 g

m(O) = 71.1 g

n(O) = 71.1 g ÷ 16 g/mol

n(O) = 4.4 mol; amount of oxygen

4) n(C) : n(H) : n(O) = 2.2 mol : 2.2 mol : 4.4 mol /2.2 mol.

n(C) : n(H) : n(O) = 1 : 1 : 2

M(CHO₂) = 45 amu; empirical formula

90 amu ÷ 45 amu = 2 CHO₂

More info about empirical formula: brainly.com/question/1873039

#SPJ4

5 0
1 year ago
How many liters are in 555 g of O2
victus00 [196]

Answer:

388.5

Explanation:

\frac{555}{32}  = 17.34375 \\ 17.34375  \times 22.4 = 388.5

3 0
4 years ago
When two moles of ethane react completely with oxygen, how many moles of carbon dioxide will be produced?A. 2.B. 4.C. 8.D. Unkno
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Answer:

Option B.

Explanation:

As any reaction of combustion, the O₂ is a reactant and the products are CO₂ and H₂O. Combustion reaction for ethane is:

2C₂H₆  +  7O₂   →   4CO₂  +  6H₂O

So 2 moles of ethane react with 7 moles of oxygen to make 4 moles of dioxide and 6 moles of water.

Then 2 moles of ethane will produce 4 moles of CO₂

6 0
3 years ago
Please answer correctly ...I will mark you brainliest
Valentin [98]

Answer:

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4 0
4 years ago
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