Answer:
Double=4 and triple=6
Explanation:
This is because double bonds are two pairs of electrons are shared between atoms and triple bonds are three pairs, and one pair of electrons is 2, so 2 x 2=4 and 2 x 3=6.
Answer:
9.18g
Explanation:
Step 1: Write the reduction half-reaction
Au³⁺(aq) + 3 e⁻ ⇒ Au(s)
Step 2: Calculate the mass of gold is produced when 15.0A of current are passed through a gold solution for 15.0min
We will use the following relationships:
- 1 mole of electrons has a charge of 96486 C (Faraday's constant).
- 1 mole of Au is produced when 3 moles of electrons circulate.
- The molar mass of Au is 196.97 g/mol.
The mass of gold produced is:

Answer is 355 grams.
Explanation:
Given the molecular weights:
M
r
N
a
O
H
=
40
g
m
o
l
M
r
N
a
2
S
O
4
=
142
g
m
o
l
The analogy of the moles will be held constant:
n
N
a
O
H
n
N
a
2
S
O
4
=
2
1
n
N
a
O
H
n
N
a
2
S
O
4
=
2
For each one, substitute:
n
=
m
M
r
Therefore:
n
N
a
O
H
n
N
a
2
S
O
4
=
2
m
N
a
O
H
M
r
N
a
O
H
m
N
a
2
S
O
4
M
r
N
a
2
S
O
4
=
2
200
40
x
142
=
2
200
⋅
142
40
x
=
2
200
⋅
142
=
2
⋅
40
x
x
=
200
⋅
142
2
⋅
40
=
100
⋅
142
40
=
10
⋅
142
4
=
1420
4
=
=
710
2
=
355
g
r
a
m
s
(or just use a calculator)
860 mL.
<h3>Explanation</h3>
Separate this process into two steps:
- Cool the balloon from 305 K to 265 K.
- Reduce the pressure on the balloon from 0.45 atm to 0.25 atm.
What would be the volume of the balloon after each step?
After Cooling the balloon at constant pressure:
By Charles's Law, the volume of a gas is directly related to its temperature in degrees Kelvins.
In other words,
,
where
and
are volumes of the same gas.
and
are the temperatures (in degrees Kelvins) of that gas.
Rearranging,
.
The balloon ended up with a lower temperature. As a result, its volume drops:
.
After reducing the pressure on the balloon at constant temperature:
By Boyle's Law, the volume of a gas is inversely proportional to the pressure on this gas.
In other words,
,
where
and
are volumes of the same gas.
and
are the pressures on this gas.
Rearranging,
.
There's now less pressure on the balloon. As a result, the balloon will gain in volume:
.
The final volume of the balloon will be
.