Ask question

Ask question

All categories

MA_775_DIABLO [31]

3 years ago

7

What makes landing the hot air balloon a challenge?

1 answer:

Mariana [72]3 years ago

7 0

You have to think about the fact that hot air is constantly being blown up elevating the balloon once that air is taken away it's up to the steering and the wind after that. I know that probably doesn't help did you want to know the science part?

You might be interested in

A reaction is spontaneous if ΔG is ___?<br> negative, positive, or zero?

amm1812

Answer:

A reaction is spontaneous if ΔG is negative.

Explanation:

The change in free energy (ΔG) is the difference between the heat released during a process and the heat released for the same process occurring in a reversible manner.

The sign of ΔG gives an indication for the spontaneity of the reaction:

If ΔG is negative, the reaction is spontaneous.

If ΔG = zero, the reaction is at equilibrium.

If ΔG is positive, the reaction is non-spontaneous.

3 0

3 years ago

What mass of sucrose, C12H22011, is needed to make 500.0 mL of a 0.200M<br> solution?

NeX [460]

Answer:

34.23 g

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

7 0

3 years ago

Jill said that when you are standing in front of a fire you are warm because you release the coolness of your body to the heat o

Tju [1.3M]

Greg is correct, Jill is wrong. Only heat can be released.

6 0

3 years ago

The chemical formula for disulfur monoxide is:<br> A. S2O<br> B. 2SO<br> C. SO2<br> D. S2O2

Delvig [45]

The answer is (A).
Hope this helps :).

3 0

3 years ago

A 3.0-L sample of helium was placed in container fitted with a porous membrane. Half of the helium effused through the membrane

zhenek [66]

Explanation:

It is known that rate of effusion of gases are inversely proportional to the square root of their molar masses.

And, half of the helium (1.5 L) effused in 24 hour. So, the rate of effusion of He gas is calculated as follows.

$\frac{1.5 L}{24 hr}$

= 0.0625 L/hr

As, molar mass of He is 4 g/mol and molar mass of $O_{2}$ is 32 g/ mol.

Now,

$\frac{\text{Rate of He}}{\text{Rate of Oxygen}} = \sqrt{\frac{32}{4}$

= 2.83

or, rate of $O_{2} = \frac{\text{Rate of He}}{2.83}$

= $\frac{0.0625 L/hr}{2.83}$

Rate of $O_{2}$ = 0.022 L/hr.

This means that 0.022 L of $O_{2}$ gas effuses in 1 hr

So, time taken for the effusion of 1.5 L of $O_{2}$ gas is calculated as follows.

$\frac{1.5 L}{0.022 L/hr}$

= 68.18 hour

Thus, we can conclude that 68.18 hours will it take for half of the oxygen to effuse through the membrane.

3 0

3 years ago