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riadik2000 [5.3K]
3 years ago
9

Suggest two reasons why copper should not be disposed of in landfill sites

Chemistry
1 answer:
Dmitry [639]3 years ago
5 0

Copper should not be disposed of in landfill sites because the dust and waste gases of copper is very harmful to the environment. It can leached into the ground possibly affecting the underground water.

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What is the mass of Al₂O3 that will contain 10 kg of aluminium?​
Oksanka [162]

Answer:

1 mole of Al2O3 = 102 grams

1 mole of Al2 = 54 grams

102 grams of Al2O3 contains = 54 gram of Al2

10kg of Al2O3 contains = (54/102)*10000g Al2

= 5294.11 g Al2 or 5.29411 kg

5 0
2 years ago
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Sometimes described as a "chemical brother" of gaba (gamma-aminobutyric acid), which amino acid neurotransmitter acts in an exci
poizon [28]

excitatory amino acids are the amino acids helps in transformation of neurotransmitters or it helps in transmission of synapsis rapidly in brain of mammal. EAA known to be neurotransmitters for Central nervous system.

Excitatory amino acids count may vary from 50’s to 100’s. They are mostly composed of non-protein- amino acids obtained from algae or fungi.

The possible EAAs are Glutamate (Glu) and Aspartate which act as excitatory neurotransmitters in the brain. They get released from neurons where they induce excitation via metabotropic Glu receptors.  

Both glutamate and aspartate having excitatory effect on neurotransmission whereas Gama-amino butyric acid having inhibitory effect on neurotransmission.

Thus, the statement ‘neurotransmitters are chemical brother of gaba’ is indicating the complementary effect of each other.


4 0
3 years ago
Find the % composition for each element in Zn(CIO3)2
bezimeni [28]

Zn = 28.15%

Cl = 30.53%

O = 41.32%

<h3>Further explanation</h3>

Given

Zn(CIO3)2 compound

Required

The % composition

Solution

Ar Zn = 65.38

Ar Cl = 35,453

Ar O = 15,999

MW Zn(CIO3)2 = 232.3

Zn = 65,38/232.3 x 100% = 28.15%

Cl = (2 x 35.453) / 232.3 x 100% = 30.53%

O = (6 x 15.999) / 232.3 x 100% = 41.32%

7 0
2 years ago
I have coronia virus say something positive to help me through
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you're a strong person so keep on keeping on.

Explanation:

8 0
3 years ago
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Calculate the empirical formula the compound with the following percent composition: 27.59%C 1.15%H 16.09%N 55.17%O
jeyben [28]

Answer: C2HNO3

Explanation: C = 27.59/12.011 = 2.297

H = 1.15/1.008 = 1.1409

N = 16.09/14.007 = 1.1487

O = 55.17/15.999 = 3.4483

Divide by smallest result:

C = 2

H=1

N=1

O = 3

Empirical formula = C2HNO3

8 0
3 years ago
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