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2 years ago

3pr - 4ps + 12qs - 9qr = ?

Mathematics

1 answer:

aleksklad [387]2 years ago

4 0

It cannot be simplified more than that. hope this helps!

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In a bag of sweets, 6 are orange and 9 are lime. Jodi chooses a sweet at random, eats it an

Digiron [165]

Answer: $\frac{17}{35}$

Step-by-step explanation:

Given

The bag contains 6 orange and 9 lime sweets

For both sweets of the same flavor, Jodi must either choose orange or lime

No. of ways it can be done is $^6C_1\times^5C_1+^9C_1\times^8C_1$

The total no of ways of selecting two sweets out of 15 is $^{15}C_1\times^{14}C_1$

The probability that both sweets are the same flavor

$P=\dfrac{^6C_1\times^5C_1+^9C_1\times^8C_1}{^{15}C_1\times^{14}C_1}=\frac{102}{210}=\frac{51}{105}=\frac{17}{35}$

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2 years ago

Which is better to buy a 12.5 oz bag of Doritos for $3.79 or a 3 oz bag for $1.00. Write each rate

ioda

$3.79 /12.5 = .3032

1/3 = .333

The 12.5 oz bag is cheaper

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3 years ago

Mercury is the closest planet to the sun at a distance of 36 million miles. The closest star to the sun is Proxima Centauri, whi

borishaifa [10]

Answer:

Proxima Centauri is 2.478 x 10¹³ miles from Sun.

Explanation:

Distance of Proxima Centauri to sun = 4.24 light years

1 light year = 5.9 x 10¹² miles.

Distance of Proxima Centauri to sun in miles = Distance in light years x 5.9 x 10¹² miles

So, Distance of Proxima Centauri to sun in miles = 4.2 x 5.9 x 10¹² miles

= 2.478 x 10¹³ miles

So Proxima Centauri is 2.478 x 10¹³ miles from Sun.

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2 years ago

Sam has a water bottle that holds 250 milliliters of water when full. He needs to fill a 5-liter water jug for his team. If Sam

stealth61 [152]

There are 1000ml in 1L. There for there are 4x250ml in 1L. Multiply 5x4 gives you 20. Therefore he needs to fill 20 water bottles to fill the jug

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2 years ago

Read 2 more answers

Which expression is equivalent to

rodikova [14]

Step-by-step explanation:

$\log_{12}\left(\dfrac{\frac{1}{2}}{8w}\right)=\log_{12}\left(\dfrac{1}{16w}\right)\qquad\text{use}\ a^{-1}=\dfrac{1}{a}\\\\=\log_{12}(16w)^{-1}\qquad\text{use}\ \log_ab^n=n\log_ab\\\\=-1\log_{12}(16w)\qquad\text{use}\ \log_a(bc)=\log_ab+\log_ac\\\\=-\left(\log_{12}16+\log_{12}w\right)=-\log_{12}2^4-\log_{12}w\qquad\text{use}\ \log_ab^n=n\log_ab\\\\=-4\log_{12}2-\log_{12}w$

8 0

3 years ago

3pr - 4ps + 12qs - 9qr = ?​

3pr - 4ps + 12qs - 9qr = ?