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puteri [66]
2 years ago
13

Sam and Paul started a business. Their investments were in the ratio 6:7, respectively. How much did Paul invest if Sam's invest

ment was $828?
Mathematics
1 answer:
Pani-rosa [81]2 years ago
8 0

Answer:

$966

Step-by-step explanation:

Sam's investment = 828

Paul's investment will be temporarily marked as x.

We need to divide 828 by 6 = 138 to find the result, x.

We multiply that by 7. 7 x 138 = 966.

We can write in 3 different ways:

828 : 966

828/966

(or in fraction form, I don't have a fraction line.

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Can you help me with this question please
solniwko [45]

Answer:

the answer is 9^8

Step-by-step explanation:

9^3 * 9^5 = 9^ 3 + 5 = 9^8

7 0
3 years ago
A train left for Houston, and 7 hours later, a car traveling 62 mph tried catching up to the train. After 4 hours, the car caugh
lana [24]

Answer: 22.55 mph

Step-by-step explanation:

Let the speed of the train be n

4 × 62 = 248 which is the distance travelled by the car in 4 hours and the train travelled in 11 hours

11 × n = 248

11n = 248

n = 248/11

n = 22.55mph

5 0
3 years ago
If you invest $5000 in an account 10 years at a 3% interest rate, how much money will you have?
Tanya [424]
I=prt..... i=5000*10*0.03=1500 5000+1500=6500
7 0
3 years ago
The Ace Novelty company produces two souvenirs: Type A and Type B. The number of Type A souvenirs, x, and the number of Type B s
Molodets [167]

Answer:

  500 type A; 3500 type B

Step-by-step explanation:

The method of Lagrange multipliers can solve this quickly. For objective function f(x, y) and constraint function g(x, y)=0 we can set the partial derivatives of the Lagrangian to zero to find the values of the variables at the extreme of interest.

These functions are ...

  f(x,y)=4x+2y\\g(x,y)=2x^2+y-4

The Lagrangian is ...

  \mathcal{L}(x,y,\lambda)=f(x,y)+\lambda g(x,y)\\\\\text{and the partial derivatives are ...}\\\\\dfrac{\partial \mathcal{L}}{\partial x}=\dfrac{\partial f}{\partial x}+\lambda\dfrac{\partial g}{\partial x}=4+\lambda (4x)=0\ \implies\ x=\dfrac{-1}{\lambda}\\\\\dfrac{\partial \mathcal{L}}{\partial y}=\dfrac{\partial f}{\partial y}+\lambda\dfrac{\partial g}{\partial y}=2+\lambda (1)=0\ \implies\ \lambda=-2

  \dfrac{\partial\mathcal{L}}{\partial\lambda}=\dfrac{\partial f}{\partial\lambda}+\lambda\dfrac{\partial g}{\partial\lambda}=0+2x^2+y-4=0\ \implies\ y=4-2x^2\\\\\text{We know $\lambda$, so we can find x and y:}\\\\x=\dfrac{-1}{-2}=0.5\\\\y=4-2\cdot 0.5^2=3.5

Since x and y are in thousands, maximum profit is to be had when the company produces ...

  500 Type A souvenirs, and 3500 Type B souvenirs

3 0
3 years ago
Find all​ x-values where the function is discontinuous.
tamaranim1 [39]
The function is discontinuous at x=8 because as x approaches 8 from the left, f(x) approaches -1 but as x approaches 8 from the right, f(x) approaches 1 and -1 and 1 are not equal.
7 0
2 years ago
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