Question

What are the zeros of the polynomial function f(x)=x^3-5x^2-6x ?

Answer 1

Answer:

D is the right answer

Step-by-step explanation:

Answer 2

Option C

The zeros of the polynomial function f(x) = x^3 - 5x^2 - 6x is x = 0 and x = -1 and x = 6

Solution:

Given that polynomial function is f(x) = x^3 - 5x^2 - 6x

We have to find the zeros of polynomial

To find zeros, equate the given polynomial function to 0. i.e f(x) = 0

$x^3 - 5x^2 - 6x = 0$

Taking "x" as common term,

$x(x^2 - 5x - 6) = 0$

Equating each term to zero, we get

$x=0 \text { and } x^{2}-5 x-6=0$

Thus one of the zeros of function is x = 0

Now let us solve $x^{2}-5 x-6=0$

We can rewrite -5x as -6x + x

$x^2 + x - 6x - 6 = 0$

Taking "x" as common from first two terms and -6 as common from next two terms

$x(x + 1) -6(x + 1) = 0$

Taking (x + 1) as common term,

(x + 1)(x - 6) = 0

x + 1 = 0 and x - 6 = 0

x = -1 and x = 6

Thus the zeros of given function is x = 0 and x = -1 and x = 6