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nirvana33 [79]
3 years ago
15

Two mechanics worked on a car. First mechanic worked 20 hours, and the second worked 5 hours. Together the charged $1800. What w

as the rate charge by each if the some of both rates was 135 per hour?
Mathematics
1 answer:
kipiarov [429]3 years ago
6 0

Answer:

Step-by-step explanation:

let one charge=x

second charge=135-x

20x+(135-x)5=1800

4 x+135-x=360

3x=360-135=225

x=75 $

first charges $ 75 for 20 hours

second charges =135-75=$60 for 5 hours.

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Suppose that an airline quotes a flight time of 128 minutes between two cities. Furthermore, suppose that historical flight reco
ANTONII [103]

Answer:

(a) The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{b-a};\ a

(b) The value of P (129 ≤ X ≤ 146) is 0.3462.

(c) The probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

Step-by-step explanation:

The random variable <em>X</em> is defined as the flight time between the two cities.

Since the random variable <em>X</em> denotes time interval, the random variable <em>X</em> is continuous.

(a)

The random variable <em>X</em> is Uniformly distributed with parameters <em>a</em> = 10 minutes and <em>b</em> = 154 minutes.

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{b-a};\ a

(b)

Compute the value of P (129 ≤ X ≤ 146) as follows:

Apply continuity correction:

P (129 ≤ X ≤ 146) = P (129 - 0.50 < X < 146 + 0.50)

                           = P (128.50 < X < 146.50)

                           =\int\limits^{146.50}_{128.50} {\frac{1}{154-102}} \, dx

                           =\frac{1}{52}\times \int\limits^{146.50}_{128.50} {1} \, dx

                           =\frac{1}{52}\times (146.50-128.50)

                           =0.3462

Thus, the value of P (129 ≤ X ≤ 146) is 0.3462.

(c)

It is provided that a randomly selected flight between the two cities will be at least 3 minutes late, i.e. <em>X</em> ≥ 128 + 3 = 131.

Compute the value of P (X ≥ 131) as follows:

Apply continuity correction:

P (X ≥ 131) = P (X > 131 + 0.50)

                 = P (X > 131.50)

                 =\int\limits^{154}_{131.50} {\frac{1}{154-102}} \, dx

                 =\frac{1}{52}\times \int\limits^{154}_{131.50} {1} \, dx

                 =\frac{1}{52}\times (154-131.50)

                 =0.4327

Thus, the probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

6 0
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Step-by-step explanation:

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4 0
2 years ago
Matthew completed 5/8 of his workday. What decimal would also describe the portion of the workday he has finished? How can you u
Natalija [7]

Answer:

a)D= 0.625 Decimal that describes the portion of the workday he has finished

b)P= D*100= 0.625*100=62.5%

P: percentaje

D: Decimal

Step-by-step explanation:

Nomenclature

F: fraction of daily workday

D: decimal of daily workday

P: percentage of daily workday

Formulas

F= a/b

D= a÷b

P= D*100

Problem development

We have:

F = 5/8, then:

D= 5÷8= 0.625

To obtain the percentage of the workday that Matew has completed, we multiply the decimal x 100

P= 0.625*100=62.5%

6 0
3 years ago
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