Answer:
a. Emily should begin her turn as the third driver at point (1, -0.5).
b. Emily's turn to drive end at point (-2.5, -3.75).
Step-by-step explanation:
Let assume that the group of girls travels from their hometown to San Antonio in a straight line. We know that each location is, respectively:
Hometown

San Antonio

Then, we can determine the end of each girl's turn to drive by the following vectorial expression based on the vectorial equation of the line:
Steph
(1)
![S(x,y) = (8,6) + \frac{1}{4}\cdot [(-6,-7)-(8,6)]](https://tex.z-dn.net/?f=S%28x%2Cy%29%20%3D%20%288%2C6%29%20%2B%20%5Cfrac%7B1%7D%7B4%7D%5Ccdot%20%5B%28-6%2C-7%29-%288%2C6%29%5D)


Andra
(2)
![A(x,y) = (8,6) + \frac{2}{4}\cdot [(-6,-7)-(8,6)]](https://tex.z-dn.net/?f=A%28x%2Cy%29%20%3D%20%288%2C6%29%20%2B%20%5Cfrac%7B2%7D%7B4%7D%5Ccdot%20%5B%28-6%2C-7%29-%288%2C6%29%5D)


Emily
(3)
![E(x,y) = (8,6) + \frac{3}{4}\cdot [(-6,-7)-(8,6)]](https://tex.z-dn.net/?f=E%28x%2Cy%29%20%3D%20%288%2C6%29%20%2B%20%5Cfrac%7B3%7D%7B4%7D%5Ccdot%20%5B%28-6%2C-7%29-%288%2C6%29%5D)


a. <em>If the girls take turns driving and each girl drives the same distance, at what point should they stop from Emily to begin her turn as the third driver? </em>
Emily's beginning point is the Andra's stop point, that is,
.
Emily should begin her turn as the third driver at point (1, -0.5).
b. <em>At what point does Emily's turn to drive end?</em>
Emily's turn to drive end at point (-2.5, -3.75).
6 minivans are needed to take (i think I'm real bad at math)
Volume of cylinders = pi x r^2 x height Simplifying the ratio: 1.6/3 = 16 / 30 (multiply and divide by 10 to remove the decimal) Volume Ratio = 512:27
Answer:
he pays 4320 :)
Step-by-step explanation:
Answer:
The height of the cylinder is 4x units.
Step-by-step explanation:
volume of a cylinder = nr^2h
n = 22/7
r = radius = x/2
Let illustrate with an example. If the diameter of a cylinder is 6 and the volume is 6^3 = 216. The radius = 6/2 = 3
n3^2 x h = 216
h = 216/9 = 24
so the height is 4 times the diameter
Area of the base = nr^2
1/2^2 x x = 1/4 pi x^2