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3 years ago

5

How do you post a picture

1 answer:

BARSIC [14]3 years ago

4 0

Click the ask a question button or answer button then at the bottom above the keyboard there are two little icons. A camera lens and a Mountain View. If you click the camera lens you can take a picture to post and if you click the Mountain View it will give you the option to post a picture from your photos.

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Can someone help me please

Vedmedyk [2.9K]

The correct answer would be

Mile

3 0

3 years ago

How does a scientific theory compare to a scientific law?

shusha [124]

Answer:

In general, a scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory. It is a misconception that theories turn into laws with enough research.

Explanation:

Hope this helped

6 0

3 years ago

Read 2 more answers

The design of a 60.0 cm industrial turntable requires that it has a kinetic energy of 0.250 j when turning at 45.0 rpm. What mus

Aneli [31]

Answer:

The moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²

Explanation:

Given;

radius of the turnable, r = 60 cm = 0.6 m

rotational kinetic energy, E = 0.25 J

angular speed of the turnable, ω = 45 rpm

The rotational kinetic energy is given as;

$E_{rot} = \frac{1}{2} I \omega ^2$

where;

I is the moment of inertia about the axis of rotation

ω is the angular speed in rad/s

$\omega = 45 \frac{rev}{\min} \times \frac{2 \pi \ rad}{1 \ rev} \times \frac{1 \ \min}{60 \ s} \\\\\omega = 4.712 \ rad/s$

$E = \frac{1}{2} I \omega ^2\\\\I = \frac{2E}{\omega ^2} \\\\I = \frac{2 \ \times \ 0.25}{(4.712)^2} \\\\I = 0.0225 \ kg.m^2$

Therefore, the moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²

5 0

3 years ago

Weight is measured in units called

Aleksandr-060686 [28]

Pounds

If you are talking about the unit of measurement for weight is that of force it would be Newtons.

8 0

3 years ago

To get an idea of the size of magnetic fields at the atomic level, consider the magnitude of the magnetic field due to the elect

artcher [175]

Answer:

The magnetic field is 14.08 T.

Explanation:

Given that,

Speed of electron $v=2.2\times10^{6}\ m/s$

Distance $d =0.5\times10^{-10}\ m$

Suppose we need to find the magnetic field at the location of the proton

We need to calculate the magnetic field

Using formula of magnetic field

$B = \dfrac{\mu_{0}I}{2r}$ ....(I)

Using formula of current

$I=\dfrac{q}{T}$

Using formula of time

$T= \dfrac{2\pi r}{v}$

Put the value of current and time in equation (I)

$B=\dfrac{\mu \times q\times v}{2\pi r\times2r}$

Put the value into the formula

$B=\dfrac{4\pi\times10^{-7}\times1.6\times10^{-19}\times2.2\times10^{6}}{4\pi\times(0.5\times10^{-10})^2}$

$B=14.08\ T$

Hence, The magnetic field is 14.08 T.

3 0

3 years ago