Answer:
D.
a heat force generated by the flames
Explanation:
Im not sure if that is right. the answer also maybe C.
At the initial state: v1 = vf = 0.001053 m
3
/kg, h1 = hf = 467.11 kJ/kg, and s1 = sf = 1.4336 kJ/kgK.
The mass of the water is: m = V/v1 = 0.005/0.001053 = 4.7483 kg.
To find the final state, we will use the First Law:
Q12 = m(h2 - h1) for closed system undergoing a constant pressure process.
h2 = 1Q2/m + h1 = 2200/4.7483 + 467.11 = 930.43 kJ/kg.
At P2 = P1 = 150 kPa, this is a saturated mixture.
hf = 467.11 kJ/kg, hfg = 2226.5 kJ/kg, sf = 1.4336 kJ/kgK, and sfg = 5.7897 kJ/kgK
s2 = sf + sfg (h2 – hf )/hfg = 1.4336 + 5.7897(930.43 – 467.11)/2226.5 = 2.6384 kJ/kgK.
The entropy change of water is:
Delta Ssys= m(s2 – s1) = 4.7483(2.6384 – 1.4336) = 5.72 kJ/K.
Given :
Mass of person, m = 81 kg.
Area of high heal, A = 3.5 cm² = 0.00035 m².
To Find :
The pressure applied by the heal on the ground.
Solution :
We know, pressure is given by :
Hence, this is the required solution.
According to first parity rule in a double stranded DNA %A=%T and %G=%C
<span> which means Adenine-Thymine and Guanine-Cytosine these pairs are present in equal amounts
</span>
<span>a = (v2 - v1)/t = (10 - 6)/2 = 2 m/sec/sec (average acceleration)</span>
