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Helga [31]
3 years ago
10

What connects neurons and what chemicals help neurons communicate

Physics
2 answers:
Vaselesa [24]3 years ago
7 0
The neurons are connected, with a tiny gap between them called the synapse, by dendrites. Neurotransmitters are chemical compounds that carry signals across the synapse.
cluponka [151]3 years ago
4 0

Answer:

synapses

The chemical that helps them to communicate is neurotransmitters

Explanation: synapses have a receiving end and a sending end that helps them receive signal transmitted through the neurotransmitters

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What label should mateo place in the marked cell? uses electrical energy provides electrical energy measures electric current co
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The product label which Mateo should place in the marked cell is that it: B. provides electrical energy.

<h3>What is a product label?</h3>

A product label can be defined as a paper-document with specific information about the chemical elements, nutrients, and other chemical compounds that are present in a product and its general use or function.

In this scenario, the product label which Mateo should place in the marked cell shown in the image attached below is that, this product was designed and developed to provide electrical energy, based on the electrical symbol for battery.

Read more on product label here: brainly.com/question/14446515

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Which is a valid velocity reading for an object?
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Explanation:

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nata0808 [166]

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Explanation:

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Convert 300mil per hr to km per hr​
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An object is dropped from an altitude of one Earth radiusabove Earth's surface. If M is the mass of Earth and R is itsradius the
Montano1993 [528]

Answer:

The speed of the object just before it hits Earth is  \sqrt{\dfrac{GM}{R}}

(A) is correct option.

Explanation:

Given that,

M = mass of earth

R = radius of earth

The potential energy at height above the surface of the earth

P.E=-\dfrac{GmM}{R+h}

The kinetic energy at height above the surface of the earth

K.E = 0

The total energy at height above the surface of the earth

E = K.E+P.E

E = -\dfrac{GmM}{R+h}....(I)

The total energy at the surface of the earth

E'=\dfrac{1}{2}mv^2-\dfrac{GmM}{R}....(II)

We need to calculate the speed of the object  just before it hits Earth

From equation (I) and (II)

-\dfrac{GmM}{R+h}=\dfrac{1}{2}mv^2-\dfrac{GmM}{R}

Here, h = R

-\dfrac{GmM}{2R}=\dfrac{1}{2}mv^2-\dfrac{GmM}{R}

v= \sqrt{\dfrac{GM}{R}}

Hence, The speed of the object just before it hits Earth is  \sqrt{\dfrac{GM}{R}}.

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