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Rudiy27
1 year ago
12

C. The maximum tension the string can have without breaking is 3N. If the speed of

Physics
1 answer:
Pavel [41]1 year ago
4 0

The net force is the centripetal force is 3.56 N.

F1= 3N

F2 = m v²/r

F 2= 0.150 kg*(2.8 m/s)^2/0.75 m

F2= 0.56N

Net force = F1+F2=3N+0.56N= 3.56 N.

As an object moves, the centripetal force pulls or pushes it towards the center of a circle, generating angular or circular motion. The force of tension on the rope pushes the object towards the center while spinning a ball on a string or twirling a lasso.

Centripetal force is described as the force acting on a body traveling in a circular route that is directed toward the body's center. The name is derived from the Latin words centrum, which means "center," and petere, which means "to seek." The centripetal force is the center-seeking force.

To learn more about centripetal force visit:brainly.com/question/11324711

#SPJ9

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10 turns of wire are closely wound around a pencil as shown in the figure. when measured using a scale as shown, the length of t
Mila [183]

Answer:

a. The thickness of the wire is 2.5 mm.

b. The wire is 0.25 cm thick.

Explanation:

Number of turns of the wire = 10

The length of total turns = 25 mm

a. The thickness of the wire can be determined by;

thickness of the wire = \frac{length of total turns}{number of turns}

                           = \frac{25}{10}

                           = 2.5 mm

Therefore, the wire is 2.5 mm thick.

b. To determine the thickness of the wire in centimetre;

10 mm = 1 cm

So that,

2.5 mm = x

x  = \frac{2.5}{10}

   = 0.25 cm

The wire is 0.25 cm thick.

8 0
3 years ago
A large, 68.0-kg cubical block of wood with uniform density is floating in a freshwater lake with 20.0% of its volume above the
LenaWriter [7]

Answer:

a) V = 0.085 m^3

b) m = 17 kg

Explanation:

1) Data given

mb = 68 kg (mass for the block)

20% of the block volume is floating

100-20= 80% of the block volume is submerged

2) Notation

mb= mass of the block

Vw= volume submerged

mw = mass water displaced

V= total volume for the block

3) Forces involved (part a)

For this case we have two forces the buoyant force (B), defined as the weight of water displaced acting upward and the weight acting downward (W)

Since we have an equilibrium system we can set the forces equal. By definition the buoyant force is given by :

B = (mass water displaced) g = (mw) g   (1)

The definition of density is :

\rho_w = \frac{m_w}{V_w}

If we solve for mw we got m_w = \rho_w V_w  (2)

Replacing equation (2) into equation (1) we got:

B = \rho_w V_w g (3)

On this case Vw represent the volume of water displaced = 0.8 V

If we replace the values into equation (3) we have

0.8 ρ_w V g = mg  (4)

And solving for V we have

 V =  (mg)/(0.8 ρ_w g )

We cancel the g in the numerator and the denominator we got

V = (m)/(0.8 ρ_w)

V = 68kg /(0.8 x 1000 kg/m^3) = 0.085 m^3

4) Forces involved (part b)

For this case we have bricks above the block, and we want the maximum mass for the bricks without causing  it to sink below the water surface.

We can begin finding the weight of the water displaced when the block is just about to sink (W1)

W1 = ρ_w V g

W1 = 1000 kg/m^3 x 0.085 m^3 x 9.8 m/s^2 = 833 N

After this we can calculate the weight of water displaced before putting the bricks above (W2)

W2 = 0.8 x 833 N = 666.4 N

So the difference between W1 and W2 would represent the weight that can be added with the bricks (W3)

W3 = W1 -W2 = 833-666.4 N = 166.6 N

And finding the mass fro the definition of weight we have

m3 = (166.6 N)/(9.8 m/s^2) = 17 Kg

8 0
4 years ago
In a bike race drake drove his bike over the 1500 meter course from start to finish in 50 seconds what was his average speed
Maslowich
30m/s. ................
4 0
4 years ago
Read 2 more answers
Shondra takes notes in class. I. Electromagnetic Waves II. The ability to work - Has many forms - Mechanical III. Potential ener
3241004551 [841]

The waves that are related to both electricity and magnetism are known as (EM) waves .electromagnetic Waves' this line is about a different topic than the rest of Shondra’s notes.

<h3 /><h3>What is an electromagnetic wave?</h3>

The waves that are related to both electricity and magnetism are known as electromagnetic (EM) waves. These waves are made up of time-varying electric and magnetic fields that travel over space.

These waves, which are related to electricity and magnetism, would undoubtedly spread in space. The waves that are related to both electricity and magnetism are known as electromagnetic (EM) waves.

These waves are made up of time-varying electric and magnetic fields that travel over space. These waves, which are related to electricity and magnetism, would undoubtedly spread in space.

Hence option 1 is right because the 'Electromagnetic Waves' these line is about a different topic than the rest of Shondra’s notes.

To learn more about the electromagnetic wave refer to the link;

brainly.com/question/8553652

7 0
3 years ago
The spring is unstretched at the position x = 0. under the action of a force p, the cart moves from the initial position x1 = -8
hammer [34]
Missing figure and missing details can be found here:
<span>http://d2vlcm61l7u1fs.cloudfront.net/media%2Fdd5%2Fdd5b98eb-b147-41c4-b2c8-ab75a78baf37%2FphpEgdSbC....
</span>
Solution:
(a) The work done by the spring is given by
W= \frac{1}{2} k (\Delta x)^2 &#10;
where k is the elastic constant of the spring and \Delta x is the stretch between the initial and final position. Since x1=-8 in=-0.203 m and x2=5 in=0.127 m, we have
W= \frac{1}{2} \cdot 500 N/m \cdot (0.127m-(-0.203m))^2=27.25 J

(b) The work done by the weight is the product of the component of the weight parallel to the inclined plane and the displacement of the cart:
W_W = -F_{//} (x_2 -x_1)
where  the negative sign is given by the fact that F_{//} points in the opposite direction of the displacement of the cart, and where
F_{//}=m g sin 15^{\circ}=6 kg \cdot 9.81m/s^2 \cdot sin 15^{\circ}=15.2 N
therefore, the work done by the weight is
W_W=-15.2 N \cdot (0.203m-(-0.127m))=-5.02 J

8 0
3 years ago
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