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3 years ago

A container has a mass of 1.293 metric tons. what is the mass of the container in grams

2 answers:

6 0

This problem only needs information regarding the conversion factor of metric ton to grams. It is known that 1 metric ton is equivalent to 1000000 grams. Thus to solve for the mass of container in grams just multiply 1.293 with 1000000. The answer is 1.293 x 10^6 grams.

lbvjy [14]3 years ago

6 0

Answer:

$1.293 \times 10^{6} grams$

Explanation:

Mass of the container m = 1.293 metric tons

One metric ton is equal to one million grams

The conversion factor is

1 metric ton = $1 \times 10^{6} grams$

$1.293 metric tons \times \frac{1 \times 10^6 grams}{1 metric ton} \\\\1.293 \times 10^6 grams$

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Which of the following is not a part of dalton s atomic theory?

Alex777 [14]

c. atoms are always in motion..............

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3 years ago

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The engineer of a passenger train traveling at 25.0m/s sights a freight train whose caboose is 200m ahead on the same track. The

Vika [28.1K]

Answer:

No, there won't be a collision.

Explanation:

We will use the constant acceleration formulas to calculate,

v = u + a*t

0 = 25 + (-0.1)*t

t = 250 seconds (the time taken for the passenger train to stop)

v^2 = u^2 + 2*a*s

0 = (25)^2 + 2*(-0.1)*s

s = 3125 m (distance traveled by passenger train to stop)

If the distance traveled by freight train in 250 seconds is less than (3125-200=2925 m) than the collision will occur

Speed*time = distance

Distance = (15)*(250)

Distance = 3750 m

As the distance is way more, there won’t be a collision

5 0

3 years ago

On the way home from school, Taylor's car runs out of gas. He has to walk 25m north and 10m west in order to reach the nearest g

spin [16.1K]

Answer:

The distance is 35 m and the magnitude of the displacement is 26.93 m

Explanation:

Displacement and Distance

These are two related concepts. A moving object constantly travels for some distance at defined periods of time. The total distance is the sum of each individual distance the object traveled. It can be written as:

dtotal=d1+d2+d3+...+dn

This sum is calculated independently of the direction the object moves.

The displacement only takes into consideration the initial and final positions of the object. The displacement, unlike distance, is a vectorial magnitude and can even have magnitude zero if the object starts and ends the movement at the same point.

Taylor walks 25 m north and 10 m west. The total distance is the sum of both numbers:

d = 25 m + 10 m = 35 m

To calculate the displacement, we need to know the final position with respect to the initial position. If we set the coordinates of Taylor's car as the origin (0,0), then his final position is (-10,25), assuming the west direction is negative and the north direction is positive.

The magnitude of the displacement is the distance from (0,0) to (-10,25):

$D=\sqrt{(25-0)^2+(-10-0)^2}$