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4 years ago

A container has a mass of 1.293 metric tons. what is the mass of the container in grams

2 answers:

6 0

This problem only needs information regarding the conversion factor of metric ton to grams. It is known that 1 metric ton is equivalent to 1000000 grams. Thus to solve for the mass of container in grams just multiply 1.293 with 1000000. The answer is 1.293 x 10^6 grams.

lbvjy [14]4 years ago

6 0

Answer:

$1.293 \times 10^{6} grams$

Explanation:

Mass of the container m = 1.293 metric tons

One metric ton is equal to one million grams

The conversion factor is

1 metric ton = $1 \times 10^{6} grams$

$1.293 metric tons \times \frac{1 \times 10^6 grams}{1 metric ton} \\\\1.293 \times 10^6 grams$

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Shalnov [3]

Answer:

The final velocity is $u_f = 3.44 \ m/s$

Explanation:

From the question we are told that

The mass of the child is $m_1 = 20 \ kg$

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The initial speed of the wagon is $u_w = 3.3 \ m/s$

The mass of the ball is $m_2 = 1.0 \ kg$

The initial speed off the ball is $u_2 = 3.3 \ m/s$

Generally the initial speed of the system (i.e the child , wagon , ball) is

$u_1 = u_w = u_2 = u =3.3 \ m/s$

Generally from the law of linear momentum conservation

$p_i = p_f$

Here $p_i$ is the momentum of the system before the ball is dropped which is mathematically represented as

$p_i = ( m_1 + m_2 + m_3 ) * u$

=> $p_i = ( 20 + 4 + 1 ) * 3.3$

=> $p_i = 82.5 \ kg \cdot m/s$

and

$p_f$ is the momentum of the system after the ball is dropped which is mathematically represented as

$p_f = ( m_1 + m_w ) * u_f$

=> $p_i = ( 20 + 4 ) * u_f$

$82.5 = 24 * u_f$

=> $u_f = 3.44 \ m/s$

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