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Fudgin [204]
3 years ago
8

Find two solutions to y=4x+3 use x=0 and x=4

Mathematics
2 answers:
sattari [20]3 years ago
6 0

y=3 and y=19 are your 2 solutions


Crazy boy [7]3 years ago
4 0
(for x=0) 3 & (for x=4) 19
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(-2)(4) - 7^2 help me
wlad13 [49]

Answer:

(-2)(4) - 7^2

-8-7^2

-8-49

=-57

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the area of the circle whose equation is x2+y2=6x-8y​
Semenov [28]

Answer:

Given that the equation of a circle is :

\green{ \boxed{\boxed{\begin{array}{cc}  {x}^{2}  +  {y}^{2}  = 6x - 8y \\  =  >  {x}^{2}  +  {y}^{2}   - 6x + 8y = 0 \\  =  >  {x}^{2}  +  {y}^{2}  + 2 \times ( - 3) \times x + 2 \times 4 \times y = 0 \\  \\  \sf \: standard \: equation \: o f \: circle \: is :  \\   {x}^{2}  +  {x}^{2}  + 2gx + 2fy + c = 0 \\  \\  \sf \: by \: comparing \\  \\ g =  - 3 \\ f = 4 \\ c = 0 \\  \\  \sf \: radius \:  \: r =  \sqrt{ {g}^{2}  +  {f}^{2} - c }  \\  =  \sqrt{ {( - 3)}^{2} +  {4}^{2} - 0  }  \\  =  \sqrt{9 + 16}  \\   = \sqrt{25}  \\  = 5 \: unit \\  \\  \bf \: area \:  = \pi {r}^{2}  \\  = \pi \times  {5}^{2}  \\  =\pink{ 25\pi \:  { unit }^{2} }\end{array}}}}

6 0
3 years ago
Im dying bro help The vertices of a quadrilateral are (2, 3), (3, 8), (7, 5), and (6, 2). Draw the quadrilateral in the coordina
Solnce55 [7]
Okay to the first number in the ordered pair is the x and the second is the y. So (x,y) when you put a dot on the coordinate plane such as (2,3), you have to go the the horizontal line which is x and go over right 2 spaces(depending on how many numbers is one space) then go up 3. Do that same thing for each of the order pairs. Eventually you will have 4 dots. Connect those dots then you will have the quadrilateral. I hope this helps you!
7 0
3 years ago
Approximate the zeros of the function. Round to the nearest tenth if necessary. f(x) = 4x^2 + 4x - 35. Explain each step on how
svet-max [94.6K]
4x²+4x-35=0
factor: (2x+7)(2x-5)=0
2x+7=0, or 2x-5=0
2x=-7 or 2x=5
x=-3.5 or x=2.5

I don't see any rounding necessary in this case. 

when you factor ax²+bx+c, you take the two factors of a and the two factors of c, one factor of a times one factor of c, the other factor of a times the other factors, the sum of the two products make b.
in this case, the factors of 4 is 2 and 2, the factors of -35 is -5 and 7. I line them up in the following way:
2    -5

2      7
then I multiple them diagonally, the top left 2 multiplying the bottom right 7=14, and the other 2 multiplying -5=-10, 14 and -10 make a sum of 4.

if you don't get the desired sum, switch the factors up and down till you have the right combination. Note: Do not switch left and right. 

I hope this makes sense to you.
8 0
3 years ago
Heyy! i’ll give brainliest help asap pls
vladimir1956 [14]

Answer:

I think it's A

hope this helps

have a good day :)

Step-by-step explanation:

7 0
2 years ago
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