40 dollars per 5 students=9 dollars per 1 student
divide both sides by 5.
<h3>
Answer: No, this function is not linear</h3>
This function is a hyperbola. It graphs out two disjoint curves. A linear function produces a single straight line graph. All linear functions can be written in the form y = mx+b. The x being in the denominator is one indicator we cannot write the original equation in the form y = mx+b.
y = 3/x is the same as xy = 3; this tells us every point on y = 3/x has its (x,y) coordinate pair multiply to 3.
Step-by-step explanation:
I am not fully sure what your teacher is aiming for. it friends very much on what you were just discussing in class (which I don't know).
but the first thing coming to mind is a minus sign ("-"). squaring a negative number removed the minus and makes the result equal to squaring the same positive number.
just for the undoing the 1/2 :
that is, because a fraction as exponent specifies in its denominator the root to be calculated for the basic value or expression.
so, 1/2 means square root. and yes, square is the inverse function of a square root, and it "undoes" the square root.
in exponent calculation it just means that for exponent 1 to the power of exponent 2 we simply multiply both exponents. and so, 1/2 × 2 = 1
FYI - the numerator still represents an original "to the power of" operation.
so, e.g. 3/2 would mean put the basis to the power of 3 and then do the square root of that result. or the other way around. these operations are commutative (the sequence does not matter).
Answer:
-63
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given:
u = 1, 0, -4
In unit vector notation,
u = i + 0j - 4k
Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.
If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then
u. v = 0 [<em>substitute for the values of u and v</em>]
=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k) = 0 [<em>simplify</em>]
=> v₁ + 0 - 4v₃ = 0
=> v₁ = 4v₃
Plug in the value of v₁ = 4v₃ into vector v as follows
v = 4v₃ i + v₂ j + v₃ k -------------(i)
Equation (i) is the generalized form of all vectors that will be orthogonal to vector u
Now,
Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e
Where;
|v| = 
|v| = 
= 
This is the general form of all unit vectors that are orthogonal to vector u
where v₂ and v₃ are non-zero arbitrary real numbers.
