There isn't enough info to prove the triangles to be congruent or not. So we can't say for sure either way.
We have angle CAD = angle ACB given by the arc markings, and we know that AC = AC due to the reflexive theorem. However we are missing one third piece of information.
That third piece of info could be....
- AD = BC which allows us to use SAS
- angle ACD = angle CAB which allows us to use ASA
- angle ABC = angle CDA which allows us to use AAS (slight variation of ASA)
Since we don't know any of those three facts, we simply don't have enough information.
side note: If AB = CD, then this leads to SSA which is not a valid congruence theorem. If we had two congruent sides, the angle must be between the two sides, which is what AD = BC allows.
Answer:
x = 2√7
using Pythagoras theorem:
For the bottom part:
The identification of parts A,B andC is illustrated below with their various reasons given.
<h3>What is an equilateral triangle?</h3>
An equilateral triangle is the triangle that has all its sides equal in length and each angle is made up of angle 60°.
Part A = The similar triangle are RGE and PBE
Part B = The triangles selected are similar because it was formed by an interception of the parallel lines of the rectangle GCPR.
Part C= All the sides of the equilateral triangle are the same therefore the distance from B to E and from P to E is the same with BP which is 225ft.
Learn more about triangles here:
brainly.com/question/2217700
#SPJ1
<span>2822183098.59. Convert both to meters and divide </span>
Answer:
y = x^2/ 60 + 15
=>( x - h)^2 = 4a[ (x^2/6 + 15) - k ].
Step-by-step explanation:
Okay, in order to solve this question very well, one thing we must keep at the back of our mind is that the representation for the equation of a parabola is given as ; y = ax^2 + bx + c.
That is to say; y = ax^2 + bx + c is the equation for a parabola. So, we should be expecting our answer to be in this form.
So, from the question above we are given that "the satellite dish will be in the shape of a parabola and will be positioned above the ground such that its focus is 30 ft above the ground"
We will make an assumption that the point on the ground is (0,0) and the focus is (0,30). Thus, the vertex (h,k) = (0,15).
The equation that best describes the equation of the satellite is given as;
(x - h)^2 = 4a( y - k). ------------------------(1).
[Note that if (h,k) = (0,15), then, a = 15].
Hence, (x - 0)^2 = (4 × 15) (y - 15).
x^2 = 60(y - 15).
x^2 = 60y - 900.
60y = x^2 + 900.
y = x^2/ 60 + 15.
Hence, we will have;
(x - h)^2 = 4a[ (x^2/6 + 15) - k ].
