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RideAnS [48]
3 years ago
8

What is the coefficient of x*2

Mathematics
2 answers:
dimulka [17.4K]3 years ago
7 0
X*2 = 2x

Coefficient is 2.
schepotkina [342]3 years ago
4 0
The coefficient of 2x is 2. The coefficient is always going to be the number right before the variable
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(x^3 + 5)(2x – 1)<br>(x^2 – 4)(x^2 + 4)​
earnstyle [38]

Answer:

x^{3} +x^{2} +1

Step-by-step explanation:

5 0
3 years ago
Emily is entering a bicycle race for charity. Her mother pledges $0.30 for every 0.5 mile she
sashaice [31]

Answer:

The mother will donate $5

4 0
3 years ago
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4. An airplane descends at a rate of 1,400 feet per minute. Once the airplane starts its descent, what will be its change in ele
Evgesh-ka [11]

Answer:

5600 feet

Step-by-step explanation:

If it is dropping 1400 every minute then to find the elevation at 4 minutes, you have to multiply 1400 with 4.

5 0
2 years ago
Suppose you obtain a chi-square statistic of 67.81. Are your results statistically significant if the critical value obtained fr
Svetach [21]

Answer:

Result is statistically significant.

Step-by-step explanation:

Given that :

Chisquare statistic, χ² = 67.81

Critical value for the distribution, χ²critical = 3.84

α = 0.05

The Decison region :

If χ² statistic > Critical value ; Reject H0 ; this. Eans that result is statistically significant.

Therefore, since, 67.81 > 3.84 ; This means that the result is statistically significant at 0.05

8 0
3 years ago
Drag the ordered pair that are 5.5 units apart.
Alexus [3.1K]

Answer:

  (-1.5, -3.5) and (-1.5, 2)

Step-by-step explanation:

The x-coordinates in increasing order are ...

  -3, -1.5, 5

The distances between pairs of these coordinates are ...

  -1.5 -(-3) = 1.5

  5 -(-3) = 8

  5 -(-1.5) = 6.5

Clearly, any pair with x = 5 is too far away from any pair with a different x-value.

<u>∆x = 1.5</u>

If the distance between pairs is 5.5, then the distance formula tells us the y-coordinate differences for pairs with x-coordinates of -3 and -1.5 must be ...

  d = √((x2 -x1)^2 +(y2 -y1)^2)

  5.5 = √(1.5^2 +(y2 -y1)^2) . . . substitute known values

  30.25 = 2.25 +(y2 -y1)^2 . . . . square both sides

  √28 = (y2 -y1) . . . . . . . . . . . . . . subtract 2.25 and take the square root

This value is irrational. Clearly none of the y-coordinates is irrational, so there are no point pairs with x-coordinates -3 and -1.5 that are 5.5 units apart.

__

<u>∆x = 0</u>

If the x-coordinates are the same, then the y-coordinates must differ by 5.5 in order for the points to be 5.5 units apart. The coordinates in order are ...

  for x = -1.5, y = -3.5, 2, 2.5 . . . . . differences of 5.5, 6, 0.25

  for x = 5, y = -3.5, 1.5 . . . . . . . difference of 5

The only pair we can find that is 5.5 units apart is ...

  (-1.5, -3.5) and (-1.5, 2).

6 0
2 years ago
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