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nignag [31]
3 years ago
12

How many complex roots does this have?

Mathematics
1 answer:
Vadim26 [7]3 years ago
4 0
Yes, 4 is the right answer.
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The length of a rectangle is twice the width. the perimeter of the rectangle can be expressed as 3⋅13.73. what is the width?
SVEN [57.7K]
X = width

2x + x = 3 · 13.73
3x = 41.19
x = 13.73

The width is 13.73 units.
3 0
3 years ago
Find a closed-form solution to the integral equation y(x) = 3 + Z x e dt ty(t) , x > 0. In other words, express y(x) as a fun
MrMuchimi

Answer:

y{x} = \sqrt{7+2Inx}

Step-by-step explanation:

y(x)= 3 + \int\limits^x_e {dx}/ \, ty(t) , x>0}

Let say; By y(x)= y(e)  

we have;  

y(e)= 3 + \int\limits^e_e {dt}/ \, ty= 3+0

Using Fundamental Theorem of Calculus and differentiating by Lebiniz Rule:

y^{1} (x) = 0 + 1/ xy

y^{1} = 1/xy  

dy/dx = 1/xy  

\int\limits {y} \, dxy = \int\limits \, dx/x

y^{2}/2 Inx + C

RECALL: y(e) = 3  

(3)^{2} / 2 = In (e) + C  

\frac{9}{2} =In(e)+C  

\frac{9}{2} - 1 = C

\frac{7}{2} = C  

y^{2} / 2 = In x +C

y^{2} / 2 = In x +7/2

MULTIPLYING BOTH SIDE BY 2 , TO ELIMINATE THE DENOMINATOR, WE HAVE;

y^{2} = {7+2Inx}  

y{x} = \sqrt{7+2Inx}

8 0
3 years ago
HELP PLEASE ITS DUE IN 10 MIN Use algebraic strategies to solve for x.
mr Goodwill [35]

Answer:

x = 4, x ≠ -1

Step-by-step explanation:

√3x + 4 = x

(√3x + 4)² = x² (Square both sides to get rid of the radical.)

3x + 4 = x²

0 = x² - 3x - 4 (Set everything to 0 by moving everything to one side.)

0 = (x - 4)(x + 1) (Factor.)

x = 4   x = -1

Now we need to check for extraneous solutions:

√3(4) + 4 = 4

√12 + 4 = 4

√16 = 4

4 = 4

√3(-1) + 4 = -1

√-3 +4 = -1

√1 = -1

1 ≠ -1

-1 is an extraneous solution.

8 0
3 years ago
Can someone help me on number 16....
almond37 [142]
It is 30-88 degrees I think
4 0
3 years ago
Read 2 more answers
There are 15 red, 14 green, and 9 yellow balls in a dark room. What is the minimum number of balls that Alicia needs to take so
Tems11 [23]

Answer:

32

Step-by-step explanation:

1. If you take 12 balls, 9 could be yellow and 3 could be red. We want at least 12 of the same color, so 30 balls isn't a good minimum

2. If you take 30 balls, 9 could be yellow, 10 could be red and 11 could be green.  We want at least 12 of the same color, so 30 balls isn't a good minimum.

3. If you take 31 balls, 9 could be yellow, 11 could be red and 11 could be green.  We want at least 12 of the same color, so 31 balls isn't a good minimum.

4. If you take 32 balls, 9 could be yellow, 11 could be red and 12 could be green or 9 could be yellow, 12 could be red and 11 could be green or 7 could be yellow, 13 could be red and 12 could be green or 9 could be yellow, 11 could be red and 12 could be green.

We want at least 12 of the same color, and we have it from the different samples of the 4th trial.

So, 32 balls is the minimum number of balls

8 0
3 years ago
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