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rosijanka [135]
3 years ago
12

Can someone help me with question #8 THXXx

Mathematics
1 answer:
Triss [41]3 years ago
3 0
Think it is .85 liters

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20 POINTS!
oksano4ka [1.4K]

Answer:

19

Step-by-step explanation:

idk the steps for the problem

3 0
4 years ago
-2×(-2)³×(-2)×3+(-2)×3×(-1)³
worty [1.4K]

Answer:

-90

Step-by-step explanation: I hope its the right answer. If not I'm sorry.... I'm just a kid...

3 0
3 years ago
Modeling real life last week you finish level to of a video game and 32 minutes today you finish level 2 in 28 minutes what is t
rusak2 [61]

Answer:

  -12.5%

Step-by-step explanation:

The percentage change in your time can be computed using ...

  pct change = ((new value)/(old value) -1) × 100%

  = (28/32 -1) × 100%

  = (0.875 -1) × 100% = -12.5%

The time to finish level 2 decreased by 12.5%.

6 0
3 years ago
A square has a side length that is decreasing at a rate of 8 cm per second. What is the rate of change of the area of the square
Artist 52 [7]

Answer:

<h2><em>112cm²/sec</em></h2>

Step-by-step explanation:

Area of a square is expressed as A = L² where L is the length of one side of the square.

The rate of change of area will be expressed  using chain rule as;

dA/dt = dA/dL * dL/dt where;

dL/dt is the rate at which the side length of the square is decreasing.

Given L = 7cm, dL/dt = 8cm/sec and dA/dL = 2L

dA/dL = 2(7)

dA/dL = 14cm

Substituting the given value into the chain rule expression above to get the rate of change of the area of the square, we will have;

dA/dt = dA/dL * dL/dt

dA/dt = 14cm * 8cm/sec

dA/dt = 112cm²/sec

<em>Hence, the rate of change of the area of the square when the side length is 7 cm is 112cm²/sec</em>

<em></em>

8 0
4 years ago
Debbie has two stocks, X and Y. Consider the following events:
jek_recluse [69]

Answer:

The correct answer is (D)

Step-by-step explanation:

Given the events X and Y:

X = the price of stock X has increased

Y = the price of stock Y has increased

That means that the complement of these events are:

X' = the price of stock X has not increased

Y' = the price of stock Y has not increased

Hence, the event "the price of stock X has increased and the price of stock Y has not increased" may be written as:

X ∩ Y′

3 0
3 years ago
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