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2 years ago

What is the gcf of 539 and 1540

1 answer:

3 0

Factors of 539:
1, 7, 11, 49, 77, 539

Factors of 1540:
1, 2, 4, 5, 7, 10, 11, 14, 20, 22, 28, 35, 44, 55, 70, 77, 110, 140, 154, 220, 308, 385, 770, 1540

Common Factors: 1, 7, 11, 77

GCF (greatest common factor) = 77

Hope this helps. :)

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bella needs identical strips of ribbon measuring 3.5 feet she has 85 feet in ribbon in total how many pieces of ribbon can she c

miss Akunina [59]

Bella can cut about 24 pieces because you have to divide 85 feet by 3.5 feet to find out how many pieces which is 24.285 and so on but you just round to 24.

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3 years ago

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Solve the equation for x∈Z <br><br>-x² +8x -14 ≥ 0

kenny6666 [7]

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3 years ago

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The thickness of eight pads designed for use in aircraft engine mounts are measured. The results, in mm, are 41.8, 40.9, 42.1, 4

nika2105 [10]

Answer:

We accept H₀ we don´t have enough evidence to support that the mean thickness is greater than 41 mm

Step-by-step explanation:

Sample Information:

Results:

41.8

40.9

42.1

41.2

40.5

41.1

42.6

40.6

From the table we get:

sample mean : x = 41.35

sample standard deviation s = 0.698

Hypothesis Test:

Null Hypothesis H₀ x = 41

Alternative Hypothesis Hₐ x > 41

The test is a one-tail test

If significance level is 0.01 and n = 8 we need to use t-student distribution

From t-table α = 0.01 and degree of freedom df = n - 1 df = 8 - 1

df = 7 t(c) = 2.998

To calculate t(s) = ( x - 41 ) / s/√n

t(s) = ( 41.35 - 41 ) / 0.698/√8

t(s) = 0.35 * 2.83/ 0.698

t(s) = 1.419

Comparing t(s) and t(c)

t(s) < t(c)

t(s) is in the acceptance region we accept H₀

7 0

2 years ago

Susan will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $70 and costs an ad

swat32

Answer:

350 miles

Step-by-step explanation:

Let x represent the miles driven

The cost with the first plan will be represented by 0.40x + 70

The second plan will be represented by 0.60x

Set these 2 expressions equal to each other and solve for x:

0.40x + 70 = 0.60x

70 = 0.20x

350 = x

So, Susan will have to drive 350 miles for the cost to be the same

4 0

3 years ago

the area of a rectangular volleyball court is 1800 square feet the courts length is twice it width write a system of equations t

Marianna [84]

Answer:

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

Step-by-step explanation:

Let

x ----> the length of rectangular volleyball court

y ---> the width of the rectangular volleyball court

we know that

The area of the rectangular volleyball court is equal to

$A=xy$

$A=1,800\ ft^2$

$1,800=xy$ ----> equation A

$x=2y$ -----> equation B

substitute equation B in equation A

$1,800=(2y)y$

$1,800=2y^2$

Solve for y

Simplify

$900=y^2$

take square root both sides

$y=30\ ft$

<em>Find the value of x</em>

$x=2y$

substitute the value of y

$x=2(30)=60\ ft$

therefore

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

7 0

3 years ago