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3 years ago

Please help and show work. 15 points.

Mathematics

1 answer:

djyliett [7]3 years ago

7 0

The answer is D
the x satys the same, the Y reverses positive/negative

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If m1 =53 what is m3

Thepotemich [5.8K]

Answer:

143

Step-by-step explanation:

90-53=37

180-37=143

5 0

2 years ago

Answer key for middle school math with pizzazz! book d d-47

Deffense [45]

Answer:

yea its in the book

Step-by-step explanation:

3 0

2 years ago

PLZZ could someone help me out with this and explain

jenyasd209 [6]

Answer:

It would be D because X^2 is different from 3x you would just multiply X^2 by 1 and 3x by 1 to get x^2+3x

3 0

2 years ago

Read 2 more answers

Evaluate the indefinite integral. integar x4/1 + x^10 dx

ivann1987 [24]

Answer:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c$

Step-by-step explanation:

Given

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx$

Required

Integrate

We have:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx$

Let

$u = x^5$

Differentiate

$\frac{du}{dx} = 5x^4$

Make dx the subject

$dx = \frac{du}{5x^4}$

So, we have:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx$

$\int\ {\frac{x^4}{1 + x^{10}}} \, \frac{du}{5x^4}$

$\frac{1}{5} \int\ {\frac{1}{1 + x^{10}}} \, du$

Express x^(10) as x^(5*2)

$\frac{1}{5} \int\ {\frac{1}{1 + x^{5*2}}} \, du$

Rewrite as:

$\frac{1}{5} \int\ {\frac{1}{1 + x^{5)^2}}} \, du$

Recall that: $u = x^5$

$\frac{1}{5} \int\ {\frac{1}{1 + u^2}}} \, du$

Integrate

$\frac{1}{5} * \arctan(u) + c$

Substitute: $u = x^5$

$\frac{1}{5} * \arctan(x^5) + c$

Hence:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c$

7 0

2 years ago

Based on information from Consumer Reports, a random sample of 35 thirty-gram cookies had a sample mean of 146 calories. The sta

Nonamiya [84]

Using the z-distribution, it is found that the 90% confidence interval for mean calories in a 30-gram serving of all chocolate chip cookies is (143, 149).

We are given the standard deviation for the population, which is why the z-distribution is used to solve this question.

The information given is:

Sample mean of $\overline{x} = 146$ .

Population standard deviation of $\sigma = 12$ .

Sample size of $n = 65$ .

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

The critical value, using a z-distribution calculator, for a 95% confidence interval is z = 1.645, hence:

$\overline{x} - z\frac{\sigma}{\sqrt{n}} = 146 - 1.645\frac{12}{\sqrt{35}} = 143$

$\overline{x} + z\frac{\sigma}{\sqrt{n}} = 146 + 1.645\frac{12}{\sqrt{35}} = 149$

The 90% confidence interval for mean calories in a 30-gram serving of all chocolate chip cookies is (143, 149).

A similar problem is given at brainly.com/question/16807970

8 0

2 years ago