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sleet_krkn [62]
3 years ago
7

A lever has an effort arm that is 8 meters long and the resistance arm that is 1.5 meters long, how much effort is needed to lif

t 209 newton weight?

Physics
2 answers:
sesenic [268]3 years ago
8 0

Answer: The effort force will be 8190.2 N.

Explanation:

Given that,

Effort arm = 8 m

Resistance arm = 1.5 m

Weight = 209 N

We know that,

Effort force multiply by effort arm=Weight multiply by resistance arm

F_{e}\times 8=209\times 1.5

F_{e}=8190.2 N

Hence, The effort force will be 8190.2 N.

ruslelena [56]3 years ago
6 0
We are given with two measurements of the arm and an input weight. To answer this problem,we need to balance the forces and use the lengths of the arms. 
209 N * 8 m = x * 1.5 m
x = 1114.67 N

it takes 1114.67 N to lift the input weight
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Force vector is given as

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