Answer:
The value of 60.2 mg in to g is 0.0602.
Explanation:
We need to calculate the 60.2 mg in to gram.
Conversion mg to g :
1 g = 1000 mg
Using this conversion,

So, 

Hence, The value of 60.2 mg in to g is 0.0602.
<span>The distance between you and your image changes by 2.0m. The reason for this is that you are 1m farther from the mirror and your reflection is also an additional 1m further away due to the symmetry.</span>
Answer:
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Explanation:
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Uh.. what's the question..?
The height, h to which the package of mass m bounces to depends on its initial velocity, v and the acceleration due to gravity, g and is given below:

<h3>What are perfectly elastic collision?</h3>
Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.
In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.
Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.
Since some of the Kinetic energy is converted to potential energy of the body;


Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.
Learn more about elastic collisions at: brainly.com/question/7694106