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jekas [21]
4 years ago
13

Two forces of 5N and 7N respectively act on an object.when will the resultant of two vectors be at a minimum?

Physics
2 answers:
luda_lava [24]4 years ago
7 0
When the two forces are acting in the opposite direction, then the resultant of the two vectors will be at a minimum. The value of the force will be either 2 Newton or -2 newton. <span>. It is the simplest way to prove and explain the situation under which the resultant of the two vectors will be at a minimum. The situation under which the resultant of the two vectors will be maximum is when the two forces of 5N and 7n will act in the same direction and create a combines force of 12N.</span>



Dahasolnce [82]4 years ago
7 0
When the forces act in opposite directions
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Which scientist continued the work of another while studying the elliptical path of planets? Name both scientists. Kepler advanc
Korolek [52]
This question is so vague as to render it useless.

I suspect the answer they're looking for is Kepler advanced Copernicus's work as is stated. but the way science works is that anyone who has contributed will have their work built on. for example, Newton advanced Kepler's work on the elliptical path of planets as Einstein advanced Newton's work.
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What game has worst Physics?​
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2 years ago
The current in a coil with a self-inductance of 1 mH is 2.8 A at t = 0, when the coil is shorted through a resistor. The total r
pogonyaev

Given:

L = 1 mH = 1\times 10^{-3} H

total Resistance, R = 11 \Omega

current at t = 0 s,

I_{o} = 2.8 A

Formula used:

I = I_{o}\times e^-{\frac{R}{L}t}

Solution:

Using the given formula:

current after t = 0.5 ms = 0.5\times 10^{-3} s

for the inductive circuit:

I = 2.8\times e^-{\frac{11}{1\times 10^{-3}}\times 0.5\times 10^{-3}}

I =   2.8\times e^-5.5

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5 0
3 years ago
At the beginning of 2016, robotics inc. acquired a manufacturing facility for $13.1 million. $10.1 million of the purchase price
ki77a [65]

$ 376153 is depreciation on the building for 2018.

<u>Explanation:</u>

Given data:

Original cost = $13.1 million

Residual value = $2.1 million

Useful life = 20 -year  

Depreciation on the building for 2016 = =\frac{\text {original cost-residual value}}{\text { Useful life }}

By substituting the given values, we get,

        =\frac{(\$ 13.1 \text { million }-\$ 2.1\text { million) } }{20 \text { years }}=\frac{11.1 \text { million }}{20 \text { years }} = 5500000

Depreciation for 2016 $5500000

Depreciation for 2017 $5500000

Depreciation at Dec 31, 2017 $ 5500000

In 2018, the estimates of useful life and residual value were changed to 15 years and $610000, but 2 yrs have already passed, so there're 13 more yrs to go.

Depreciation on the building for 2018,

      =\frac{\text { book value at the end of } 2016-\text {residual value}}{\text { useful life }}

        = =\frac{\$ 5500000-\$ 610000}{13}=\frac{4890000}{13}=\$ 376153

4 0
3 years ago
The wavelength you entered in the last problem is related to the energy required to eject an electron from sodium metal, the so-
I am Lyosha [343]

Answer:

2.30 eV

Explanation:

Some details of the problem are missing:

"Light of wavelength 540 nm is required to extract electrons from sodium. What is the work function of sodium?"

The equation that describes the photoelectric effect is

\frac{hc}{\lambda}=\phi +K

where:

\frac{hc}{\lambda} is the energy of the incoming photon, with

h=6.63\cdot 10^{-34} Js is Planck constant

c=3.0\cdot 10^8 m/s is the speed of light

\Phi is the work function of the material

K is the maximum kinetic energy of the emitted photoelectrons

The minimum energy needed by the photons to extract the photoelectrons is that for which the kinetic energy is zero, so

K = 0

Therefore we have

\frac{hc}{\lambda}=\phi

In this problem, we know that the wavelength of the incoming light is

\lambda=540 nm = 540\cdot 10^{-9}m

Therefore, we can find the work function of sodium:

\phi=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{540\cdot 10^{-9}}=3.68\cdot 10^{-19}J

And converting into electronvolts,

\phi=\frac{3.68\cdot 10^{-19}J}{1.6\cdot 10^{-19}}=2.30 eV

5 0
3 years ago
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