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jekas [21]
3 years ago
13

Two forces of 5N and 7N respectively act on an object.when will the resultant of two vectors be at a minimum?

Physics
2 answers:
luda_lava [24]3 years ago
7 0
When the two forces are acting in the opposite direction, then the resultant of the two vectors will be at a minimum. The value of the force will be either 2 Newton or -2 newton. <span>. It is the simplest way to prove and explain the situation under which the resultant of the two vectors will be at a minimum. The situation under which the resultant of the two vectors will be maximum is when the two forces of 5N and 7n will act in the same direction and create a combines force of 12N.</span>



Dahasolnce [82]3 years ago
7 0
When the forces act in opposite directions
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Answer:

The speed is  v =  9.8 \ m/s

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From the question w are told that

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Making v which is the speed of the fish the subject of the formula

      v =  \sqrt{ \frac{2gh_{max}}{ sin^2 \theta } }

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solniwko [45]
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3 0
3 years ago
The wavelength of red helium-neon laser light in air is 632.8 nm.(a) What is its frequency? Hz(b) What is its wavelength in glas
vekshin1
<h2>Answers:</h2>

The speed of a wave is given by:

v=f.\lambda  (1)

Where f is the frequency and  \lambda the wavelength.

In the case of light, its speed is:

c=f.\lambda (2)

On the other hand, the described situation is known as Refraction,   a phenomenon in which the light changes its direction when passing through a medium with a refractive index different from the other medium.  

In this context, the Refractive index n is a number that describes how fast light propagates through a medium or material, and is defined as the relation between the speed of light in vacuum (c=3(10)^{8}m/s) and the speed of light v in the second medium:

n=\frac{c}{v} (3)

In addition, as the light changes its direction, its wavelength changes as well:

n=\frac{\lambda_{air}}{\lambda_{glass}} (4)

Knowing this, let's begin with the answers:

<h2>a) Frequency</h2>

From equation (2) we can find f:

f=\frac{c}{\lambda}  (5)

Knowing that 1nm=(10)^{-9}m:

f=\frac{3(10)^{8}m/s}{632.8(10)^{-9}m}  

f=4.74(10)^{14}Hz}     (6)   >>>Frequency of the helium-neon laser light

<h2>b) Wavelength in glass</h2>

We already know the wavelength of the light in air \lambda_{air} and the index of refraction of the glass.

So, we only have to find the wavelength in glass \lambda_{glass} from equation (4):

\lambda_{glass}=\frac{\lambda_{air}}{n}

\lambda_{glass}=\frac{632.8(10)^{-9}m}{1.48}

\lambda_{glass}=427(10)^{-9}m=427nm   (7)   >>>Wavelength of the helium-neon laser light in glass

<h2>c) Speed in glass</h2>

From equation (3) we can find the speed vof this light in glass:

v=\frac{c}{n}

v=\frac{3(10)^{8}m/s}{1.48}

v=2.027(10)^{8}m/s   (8)  >>>Speed of the helium-neon laser light in glass

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