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3 years ago

Two forces of 5N and 7N respectively act on an object.when will the resultant of two vectors be at a minimum?

2 answers:

7 0

When the two forces are acting in the opposite direction, then the resultant of the two vectors will be at a minimum. The value of the force will be either 2 Newton or -2 newton. <span>. It is the simplest way to prove and explain the situation under which the resultant of the two vectors will be at a minimum. The situation under which the resultant of the two vectors will be maximum is when the two forces of 5N and 7n will act in the same direction and create a combines force of 12N.</span>

Dahasolnce [82]3 years ago

7 0

When the forces act in opposite directions

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Water is boiled at sea level in a coffeemaker equipped with an immersion-type electric heating element. The coffee maker contain

Luden [163]

Answer:

$P=1362\ W$

$t'=251.659\ s$ is time required to heat to boiling point form initial temperature.

Explanation:

Given:

initial temperature of water, $T_i=18^{\circ}C$

time taken to vapourize half a liter of water, $t=18\ min=1080\ s$

desity of water, $\rho=1\ kg.L^{-1}$

So, the givne mass of water, $m=1\ kg$

enthalpy of vaporization of water, $h_{fg}=2256.4\times 10^{-3}\ J.kg^{-1}$

specific heat of water, $c=4180\ J.kg^{-1}.K^{-1}$

Amount of heat required to raise the temperature of given water mass to 100°C:

$Q_s=m.c.\Delta T$

$Q_s=1\times 4180\times (100-18)$

$Q_s=342760\ J$

Now the amount of heat required to vaporize 0.5 kg of water:

$Q_v=m'\times h_{fg}$

where:

$m'=0.5\ kg=$ mass of water vaporized due to boiling

$Q_v=0.5\times 2256.4$

$Q_v=1.1282\times 10^{6}\ J$

Now the power rating of the boiler:

$P=\frac{Q_s+Q_v}{t}$

$P=\frac{342760+1128200}{1080}$

$P=1362\ W$

Now the time required to heat to boiling point form initial temperature:

$t'=\frac{Q_s}{P}$

$t'=\frac{342760}{1362}$

$t'=251.659\ s$

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4 years ago

Why do people cover their flowers on a cool night. Think about radiation absorption conduction and temperature

Blababa [14]

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3 years ago

Your high-fidelity amplifier has one output for a speaker of resistance 8 Ω. How can you arrange two 8-Ω speakers, one 4-Ω speak

ANTONII [103]

Answer:

(a) 8Ω (b) Ratio = Parra/P8 ohm = 1

Explanation:

Solution

Recall that,

An high-fidelity amplifier has one output for a speaker of resistance of = 8 Ω

Now,

(a) How can two 8-Ω speakers be arranged, when one = 4-Ω speaker, and one =12-Ω speaker

The Upper arm is : 8 ohm, 8 ohm

The Lower arm is : 12 ohm, 4 ohm

The Requirement is = (16 x 16)/(16 + 16) = 8 ohm

(b) compare your arrangement power output of with the power output of a single 8-Ω speaker

The Ratio = Parra/P8 ohm = 1

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3 years ago

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statuscvo [17]

This might help and it might not:

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liberstina [14]

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