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jekas [21]
3 years ago
13

Two forces of 5N and 7N respectively act on an object.when will the resultant of two vectors be at a minimum?

Physics
2 answers:
luda_lava [24]3 years ago
7 0
When the two forces are acting in the opposite direction, then the resultant of the two vectors will be at a minimum. The value of the force will be either 2 Newton or -2 newton. <span>. It is the simplest way to prove and explain the situation under which the resultant of the two vectors will be at a minimum. The situation under which the resultant of the two vectors will be maximum is when the two forces of 5N and 7n will act in the same direction and create a combines force of 12N.</span>



Dahasolnce [82]3 years ago
7 0
When the forces act in opposite directions
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2 years ago
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In a mass spectrometer a particle of mass m and charge q is accelerated through a potential difference V and allowed to enter a
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m = B²qR² / 2 V

Explanation:

If v be the velocity after acceleration under potential difference of V

kinetic energy  = loss of electric potential energy

1/2 m v² = Vq ,

v² = 2 Vq / m ----------------------- ( 1 )

In magnetic field , charged particle comes in circular motion in which magnetic force provides centripetal force

magnetic force = centripetal force

Bqv = mv² / R

v = BqR / m

v² = B²q²R² / m²  ------------------------- (2)

from (1) and (2)

B²q²R² / m²  = 2 Vq / m

m = B²q²R² / 2 Vq

m = B²qR² / 2 V

7 0
3 years ago
If the voltage in a circuit is 24 V and the current is 2 A, what is the total power in the circuit?
Drupady [299]
Maybe you can divide the volts its twelve if you do that but itll show you how much to double it by

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3 years ago
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The Michelson-Morley experiment was designed to measure Group of answer choices the velocity of the Earth relative to the ether.
NISA [10]

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4 0
3 years ago
Two asteroids identical to those above collide at right angles and stick together; i.e, their initial velocities were perpendicu
11111nata11111 [884]

Answer:

velocity = 62.89 m/s  in 58 degree measured from the x-axis

Explanation:

Relevant information:

Before the collision, asteroid A of mass 1,000 kg moved at 100 m/s, and asteroid B of mass 2,000 kg moved at 80 m/s.

Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.

Before collision Momentum of A = 1000 x 100 = $ 10^5$ kg - m/s in the right direction.

Before collision Momentum of B = 2000 x 80 = 1.6 x $ 10^5$  kg - m/s in upward direction.

Mass of System of after collision = 1000 + 2000 = 3000 kg

Now applying the Momentum Conservation, we get

Initial momentum in right direction = final momentum in right direction = $ 10^5$

And, Initial momentum in upward direction = Final momentum in upward direction = 1.6 x $ 10^5$

So, $ V_x = \frac{10^5}{3000} $  = $ \frac{100}{3} $  m/s

and $ V_y=\frac{160}{3}$  m/s

Therefore, velocity is = $ \sqrt{V_x^2 + V_y^2} $

                                   = $ \sqrt{(\frac{100}{3})^2 + (\frac{160}{3})^2} $

                                   = 62.89 m/s

And direction is

tan θ = $ \frac{V_y}{V_x}$     = 1.6

therefore, $ \theta = \tan^{-1}1.6 $

                   = $ 58 ^{\circ}$  from x-axis

4 0
3 years ago
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