An object of mass 5 kilograms is acted upon by the forces F and F2 as shown.
1 answer:
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Answer:
E=1760.93 cal
Explanation:
a) First we find the total time
t=x/v
t=189000/12.5
t=15120 seconds
Now we multiply the time by his total wattage
E=t*W
E=(15120)(6.5)(75)=7371000 joules
As,
1 joule = 2.389 x 10-4
So, in term of nutritional Calories
E=7371000 * 2.389*
E=1760.93 Cal