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gregori [183]
3 years ago
15

A baseball pitcher throws a ball at 40.0 m/s towards home plate. The ball is thrown horizontally. How far will it drop on its wa

y to home plate, which is 18.0 meters away?​
Physics
1 answer:
Finger [1]3 years ago
7 0

Answer:

0.992 m

Explanation:

x = (horizontal vi)t + (1/2)at²

18 = (40)t + 0

t = 0.45 s

y = (vertical vi)t + (1/2)gt²

y = 0 + (1/2)(9.8)(0.45)²

y = 0.992 m

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Which of the following is the best name for CaF2?
nikdorinn [45]
Its just Calcium Flouride because as you can see it is an Ionic bond (Ca is  metal and fl is a gas usually)
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3 years ago
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Which equation is correct according to Ohm’s law? Which equation is correct according to Ohm’s law? A.) V = IR B.) I = R/V C.) R
vodomira [7]

Answer:

V = IR

Explanation:

Required

Which equation represents ohm's law?

Literally, ohm's law implies that current (I) is directly proportional to voltage (V) and inversely proportional to resistance (R).

Mathematically, this can be represented as:

I\ \alpha\ \frac{V}{R}

Convert the expression to an equation

I\ =\ \frac{V}{R}

Multiply both sides by R to make V the subject

I\ * R\ =\ \frac{V}{R} * R

I\ * R\ =V

Reorder

V = I\ * R

V = IR

<em>Option (a) is correct; Others are not</em>

6 0
3 years ago
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At a time t = 2.80 s , a point on the rim of a wheel with a radius of 0.230 m has a tangential speed of 51.0 m/s as the wheel sl
bonufazy [111]

Answer:

Part A) the angular acceleration is α= 44.347 rad/s²

Part B) the angular velocity is 195.13 rad/s

Part C)  the angular velocity is 345.913 rad/s

Part D ) the time is t= 7.652 s

Explanation:

Part A) since angular acceleration is related with angular acceleration through:

α = a/R = 10.2 m/s² / 0.23 m =   44.347 rad/s²

Part B) since angular acceleration is related

since

v = v0 + a*(t-t0) =  51.0 m/s + (-10.2 m/s²)*(3.4 s - 2.8 s) = 44.88 m/s

since

ω = v/R = 44.88 m/s/ 0.230 m = 195.13 rad/s

Part C) at t=0

v = v0 + a*(t-t0) =  51.0 m/s + (-10.2 m/s²)*(0 s - 2.8 s) = 79.56 m/s

ω = v/R = 79.56 m/s/ 0.230 m = 345.913 rad/s

Part D ) since the radial acceleration is related with the velocity through

ar = v² / R → v= √(R * ar) = √(0.23 m  * 9.81 m/s²)= 1.5 m/s

therefore

v = v0 + a*(t-t0) → t =(v -  v0) /a + t0 = ( 1.5 m/s - 51.0 m/s) / (-10.2 m/s²) + 2.8 s = 7.652 s

t= 7.652 s

4 0
3 years ago
a swimmer can swim in still water at a speed of 9.50 m/s. he intends to swim directly across the river that has a downstream cur
Doss [256]
Refer to the diagram shown below.

Still-water speed  = 9.5 m/s
River speed = 3.75 m/s down stream.

The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.

The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s

The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°

Answer:  10.2 m/s at 21.5° downstream.

7 0
3 years ago
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Write down formula of power​
r-ruslan [8.4K]
There u go -> P=f/a
8 0
3 years ago
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