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gregori [183]
3 years ago
15

A baseball pitcher throws a ball at 40.0 m/s towards home plate. The ball is thrown horizontally. How far will it drop on its wa

y to home plate, which is 18.0 meters away?​
Physics
1 answer:
Finger [1]3 years ago
7 0

Answer:

0.992 m

Explanation:

x = (horizontal vi)t + (1/2)at²

18 = (40)t + 0

t = 0.45 s

y = (vertical vi)t + (1/2)gt²

y = 0 + (1/2)(9.8)(0.45)²

y = 0.992 m

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Answer:

Less friction

Explanation:

Paolo's bike is too difficult to pedal because there is too much friction in the mechanisms of the bike. To reduce friction, Paolo must oil the chain. This will make the bike run much more smoothly and allow for easier pedalling.

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2 years ago
Which region of the early universe was most likely to become a galaxy?
kramer

Answer:

This is likely possible for a region whose matter density is higher than the normal average.

Explanation:

A galaxy is a collection of lumps in space which are clumped together and interact with each other. There are a lot of speculations on how galaxies were birthed. some believe its formed by a collection of massive gas, dust which eventually collapsed under their own gravitational pull. others says its formed by the combination of large lumps of matter which accumulated forming thee galaxies. The possibility of a galaxy forming is dependent on how massive the matter in the region of the universe is.

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3 years ago
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How was your "therapy" session with Eliza? Describe your experience with the therapy program.
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A steam turbine operates with 1.6 MPa and 350°C steam at its inlet and saturated vapor at 30°C at its exit. The mass flow rate o
WINSTONCH [101]

Answer:

638.8kW

Explanation:

The flow rate of the steam m = 22kg/s

The Pressure of the steam at the inlet of the turbine P1 = 1.6MPa

The temperature of the steam at the inlet of the turbine T1 = 350*C

Steam quality at the exit of the turbine x2 = 1.0

The temperature of the steam at the exit of the turbine T2 = 30*C

Power produced = 12,350kW

Assuming the turbine is running on a steady state, hence we neglect the effect of kinetic and potential energy we get:

If you refer to the superheated steam table for the specific enthalpy at a pressure of 1.6MPa and temperature of 350*C, we get

h1 = 3,146kJ/kg

Refer to the steam table for saturated gas at temperature 30*C to get the specific enthalpy value h2 = 2,556.81kJ/kg

The heat that comes out from the turbine can be defined from the balance of energy in the system, and is represented as

Ein - Eout = change in system Energy = 0

Thus Ein = Eout

mh1 = mh2 + Wout + Qout

Qout = m(hi-h2) - Wout

Qout = 22 x (3146-255.6) - 12350

Qout = 638.8kW

3 0
3 years ago
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