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Andrej [43]
3 years ago
9

How do you balance a chemical equation ?

Chemistry
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

Write down your given equation. For this example, you will use:

C3H8 + O2 --> H2O + CO2

This reaction occurs when propane (C3H8) is burned in the presence of oxygen to produce water and carbon dioxide.

A chemical equation is a written symbolic representation of a chemical reaction (The symbols are the elemental letter or letters representing that element). The reactant chemical(s) are given on the left-hand side and the product chemical(s) on the right-hand side. The two are connected with an arrow leading from the left to the right, symbolizing the reaction. The law of conservation of mass states that no atoms can be created or destroyed in a chemical reaction, so the number of atoms that are present in the reactants has to balance the number of atoms that are present in the products. Follow this guide to learn how to balance chemical equations differently.[1]

Method 1 of 2:

Doing a Traditional Balance

Image titled Balance Chemical Equations Step 1

1

Write down your given equation. For this example, you will use:

C3H8 + O2 --> H2O + CO2

This reaction occurs when propane (C3H8) is burned in the presence of oxygen to produce water and carbon dioxide.

Image titled Balance Chemical Equations Step 2

2

Write down the number of atoms per element. Do this for each side of the equation. Look at the subscripts next to each atom to find the number of atoms in the equation. When writing it out, it's a good idea to connect it back to the original equation, noting how each element appears.[2]

For example, you have 3 oxygen atoms on the right side, but that total results from addition.

Left side: 3 carbon (C3), 8 hydrogen (H8) and 2 oxygen (O2).

Right side: 1 carbon (C), 2 hydrogen (H2) and 3 oxygen (O + O2).

Save hydrogen and oxygen for last, as they are often on both sides. Hydrogen and oxygen are both common in molecules, so it's likely that you'll have them on both sides of your equation. It's best to balance them last.[3]

You'll need to recount your atoms before balancing the hydrogen and oxygen, as you'll likely need to use coefficients to balance the other atoms in the equation.

Start with single elements. If you have more than one element left to balance, select the element that appears in only a single molecule of reactants and in only a single molecule of products. This means that you will need to balance the carbon atoms first.[4]

Use a coefficient to balance the single carbon atom. Add a coefficient to the single carbon atom on the right of the equation to balance it with the 3 carbon atoms on the left of the equation.[5]

C3H8 + O2 --> H2O + 3CO2

The coefficient 3 in front of carbon on the right side indicates 3 carbon atoms just as the subscript 3 on the left side indicates 3 carbon atoms.

In a chemical equation, you can change coefficients, but you must never alter the subscripts.

Balance the hydrogen atoms next. Since you have balanced all atoms besides the hydrogen and oxygen, you can address the hydrogen atoms. You have 8 on the left side. So you'll need 8 on the right side. Use a coefficient to achieve this.[6]

C3H8 + O2 --> 4H2O + 3CO2

On the right side, you now added a 4 as the coefficient because the subscript showed that you already had 2 hydrogen atoms.

When you multiply the coefficient 4 times by the subscript 2, you end up with 8.

The other 6 atoms of oxygen come from 3CO2.(3x2=6 atoms of oxygen+ the other 4=10)

Balance the oxygen atoms. Remember to account for the coefficients that you've used to balance out the other atoms. Because you've added coefficients to the molecules on the right side of the equation, the number of oxygen atoms has changed. You now have 4 oxygen atoms in the water molecules and 6 oxygen atoms in the carbon dioxide molecules. That makes a total of 10 oxygen atoms.[7]

Add a coefficient of 5 to the oxygen molecule on the left side of the equation. You now have 10 oxygen atoms on each side.

C3H8 + 5O2 --> 4H2O + 3CO2.

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Contact [7]

Answer:

O H3PO4

Explanation:

google because i looked it up

4 0
3 years ago
To understand several methods of measuring gas pressure. Gases exert a measurable pressure (P) on the walls of their container.
sammy [17]

Answer:

1. 0.9539 atm

2.  3112.732 mmHg

3. The third question is an incomplete one, as a diagram showing a gas tube with a measurement of the mercury-filled manometer should be included in the question.  This will enable easy calculation of the pressure (in atmospheres) of the gas inside the container connected to an open-end, mercury-filled manometer. However, an example is explained to give a clear understanding on how it's been calculated.

Explanation:

1. On a rainy day, a barometer reads 725 mmHg. Convert this value to atmospheres.

The answer is:

1 atm=760 mmHg=101,325 Pa

so, 725 mmHg to atm =

725 mmHg ÷ 760 mmHg = 0.9539 atm

2. A closed container is filled with oxygen. The pressure in the container is 415 kPa. What is the pressure in millimeters of mercury?

The answer is :

1 atm=760 mmHg=101,325 Pa

First, 415 kPa should be converted to pa

1 kPa = 1000 pa

415 kPa = 415,000 pa

Afterwards,  pa should be converted to atm

415,000 pa  ÷ 101,325 Pa = 4.0957 atm

Finally, atm should be converted to mmHg

4.0957 × 760 = 3112.732 mmHg

3. What is the pressure (in atmospheres) of the gas inside the container connected to an open-end, mercury-filled manometer?

The answer is:

atmospheric pressure = density of mercury x acceleration due to gravity x height of column of mercury.

Let us use for instance, 20 cmHg as the pressure in the gas. To find pressure (in atmospheres) of the gas inside the container connected to an open-end, mercury-filled manometer, we have,

 0.95atm + ( (20cmHg x 10mm) ÷ 1cm) ) x (1atm  ÷ 760mmHg) = 1.21 atm

where, 0.95atm is the atmospheric pressure.

6 0
3 years ago
Which lists mixtures, in order, from the smallest particles to the largest particles?
Kisachek [45]

Answer:

A. Solution, Colloid, Suspension

Hope i could help

4 0
4 years ago
Determine which of the following statement is correct when the equilibrium constant K for a certain reaction is 10 at 298 K and
aev [14]

Answer:

4. The reaction is spontaneous at any temperatures if the standard entropy of reaction is positive.

Explanation:

Equilibrium constant decreases on increasing the temperature . So the reaction appears to be exothermic . In other words

ΔH is negative .

Δ G = ΔH - TΔS

If ΔS is positive , second  term is negative . ΔH is negative so the RHS of the equation is negative at all temperatures . Hence Δ G of the  reaction is negative . So reaction is spontaneous at any temperature.

3 0
3 years ago
The melting point of phenol is 40.5∘C and that of toluene is −95∘C. What is the best explanation for this difference? Select the
romanna [79]

Answer:

None of the above

Explanation:

The (−OH) group on phenol can form hydrogen bonds, and the −CH3 group on toluene cannot.

Phenol has only one hydrogen on the −OH group available to form hydrogen bonds, so the hydrogen bond is stronger. In toluene, the hydrogen bond is spread over all three hydrogens on the methyl group, so the interaction is weaker overall.

Phenol has a higher molecular mass than toluene.

3 0
3 years ago
Read 2 more answers
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