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Alexxandr [17]
3 years ago
10

Determine which of the following statement is correct when the equilibrium constant K for a certain reaction is 10 at 298 K and

0.1 at 400 K?
1. The reaction is not spontaneous at any temperature if the standard entropy of reaction is positive.
2. The reaction is endothermic.
3. The reaction is not spontaneous at any temperature if the standard entropy of reaction is negative.
4. The reaction is spontaneous at any temperatures if the standard entropy of reaction is positive.
5. Cannot be determined without knowing what reaction that is.
Chemistry
1 answer:
aev [14]3 years ago
3 0

Answer:

4. The reaction is spontaneous at any temperatures if the standard entropy of reaction is positive.

Explanation:

Equilibrium constant decreases on increasing the temperature . So the reaction appears to be exothermic . In other words

ΔH is negative .

Δ G = ΔH - TΔS

If ΔS is positive , second  term is negative . ΔH is negative so the RHS of the equation is negative at all temperatures . Hence Δ G of the  reaction is negative . So reaction is spontaneous at any temperature.

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An aqueous solution containing 17.5 g of an unknown molecular (nonelectrolyte) compound in 100.0 g of water has a freezing point
Sonbull [250]

Answer:

molar mass = 180.833 g/mol

Explanation:

  • mass sln = mass solute + mass solvent

∴  solute: unknown molecular (nonelectrolyte)

∴ solvent: water

∴ mass solute = 17.5 g

∴ mass solvent =  100.0 g = 0.1 Kg

⇒ mass sln = 117.5 g

freezing point:

  • ΔTc = - Kc×m

∴ ΔTc = -1.8 °C

∴ Kc H2O = 1.86 °C.Kg/mol

∴ m: molality (mol solute/Kg solvent)

⇒ m = ( - 1.8 °C)/( - 1.86 °C.Kg/mol)

⇒ m = 0.9677 mol solute/Kg solvent

  • molar mass (Mw) [=] g/mol

∴ mol solute = ( m )×(Kg solvent)

⇒ mol solute = ( 0.9677 mol/Kg) × ( 0.100 Kg H2O )

⇒ mol solute = 0.09677 mol

⇒ Mw solute = ( 17.5 g ) / ( 0.09677 mol )

⇒ Mw solute = 180.833 g/mol

6 0
3 years ago
A particular exosolar system has five planets in total: A, B, C, D, and E. The table lists the orbital periods of these planets
sveta [45]

Answer:

The answer is in the picture below

Explanation:

8 0
3 years ago
Given the following equation, N2O(g) + NO2(g) → 3 NO(g) ΔG°rxn = -23.0 kJ
Lelechka [254]

Answer:

ΔG°rxn = -69.0 kJ

Explanation:

Let's consider the following thermochemical equation.

N₂O(g) + NO₂(g) → 3 NO(g) ΔG°rxn = -23.0 kJ

Since ΔG°rxn < 0, this reaction is exergonic, that is, 23.0 kJ of energy are released. The Gibbs free energy is an extensive property, meaning that it depends on the amount of matter. Then, if we multiply the amount of matter by 3 (by multiplying the stoichiometric coefficients by 3), the ΔG°rxn will also be tripled.

3 N₂O(g) + 3 NO₂(g) → 9 NO(g) ΔG°rxn = -69.0 kJ

8 0
4 years ago
Assume that a point mutation changes the codon AUU to AUC. Why is this a neutral mutation
lukranit [14]
I used the genetic code table. mRNA codon ===> amino acid

1st base       2nd base           3rd base
A                       U                             U               ===> Isoleucine
A                       U                             C               ===> Isoleucine

The point mutation of codon AUU to AUC is a neutral mutation because it neither benefits nor deter the ability of the organism to survive and reproduce.

As you can see, Both codons result to the Isoleucine amino acid.

Another codon that will still result to the Isoleucin amino acid is AUA.

3 0
3 years ago
HRISTINA HERRERA: Attempt 1
Lunna [17]

Answer:

7.5 g of hydrogen gas reacts with 50.0 g oxygen gas to form 57.5 g of water.

Explanation:

Here we have the check if the mass of the reactants is equal to the mass of the products.

Reactants

7.5+50=57.5\ \text{g}

Products

57.5\ \text{g}

The data is consistent with the law of conservation of matter.

Reactants

50+243=293\ \text{g}

Products

206+97=303\ \text{g}

The data is not consistent with the law of conservation of matter.

Reactant

17.7+34.7=52.4\ \text{g}

Products

62.4\ \text{g}

The data is not consistent with the law of conservation of matter.

Only the first data is consistent with the law of conservation of matter.

8 0
3 years ago
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